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It should be ~180 degrees out of phase, because a CE amplifier is an inverter.

A BJT CE amplifier is a good example to look at. The output is across CE, and at a minimum total output voltage is split across CE and some resistor R. As a higher voltage is applied to the base, the current flow through CE increases as a result of the resistance of CE decreasing.

This boils down to a simple voltage divider at the output, Vout = CE / (R + CE). As CE decreases as a result of the input increasing, Vout will decrease.

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Q: How output voltage is out of phase in CE?
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