3*sin2x = 2*sinx +1
2sinx+1 equals 0
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
4 sin2x = 1. Then, (2sinx)2 = 1, 2sinx = ±1, and sinx = ±½. Whence, x = 90° or 270°; or, in radians, x = π/2 or 3π/2.
cos2x + 2sinx - 2 = 0 (1-2sin2x)+2sinx-2=0 -(2sin2x-2sinx+1)=0 -2sinx(sinx+1)=0 -2sinx=0 , sinx+1=0 sinx=0 , sinx=1 x= 0(pi) , pi/2 , pi
0.5
First find the derivative of each term. The derivative of any constant is zero, so d(1)/dx=0. To find the derivative of cos2x, use the chain rule. d(cos2x)/dx=-sin(2x)(2)=-2sin(2x) So the answer is 0-2sinx, or simply -2sinx
That's not an equation you can solve, since it doesn't have an equal si Assuming you mean: 3x - 4y = 16 For a start, you should replace y with -1. Then solve the resulting equation: 3x - 4(-1) = 16 for x.
How do you solve y=-4x+1
Substitute secant(x)=1/cos(x) into your equation, and you should be able to solve from there.
1. Finiteness 2. Definiteness 3.
1 + 1 = 2The process used to solve it is "addition."
They are: 1.We should consult with an engeener . 2.We should alert the Govt. 3.We should fund money for it. and the list goes on.......