To find percent composition, you must work with the atomic masses. Look on a periodic chart to find the atomic masses of F and Na. You will find that Na has an Atomic Mass of 22.990 grams per mole of Na and that F has an atomic mass of 18.998 grams per mole of F.
So, add these both together, and that will tell you how much mass NaF will be. NaF will have a mass of 41.988 grams per mole of NaF.
Now to take the percent composition of F in NaF, simply divide the mass of F by the mass of NaF. That will give you [18.998/41.988]=.452 which will be about 45%.
So your answer is that F has a 45% composition of NaF.
PS: Since Na and F only had a stoichiometry of 1 (meaning there is 1 Na and 1 F in the molecule), no multiplication of the atomic masses was necessary when calculating the total mass of the molecule.
Unless graded on a curve, 40% is a F.
this is a F
C to F: C=(5/9)(F-32) F to C: F=(9/5)C+32
border line of a D and a F
It depends on the degrees of freedom for the f-test.
First, calculate the number of moles of LiF and NaF. Then, add the moles of F from both compounds and convert it to molarity by dividing by the total volume of the solution in liters. Remember to account for the stoichiometry of each compound to determine the moles of F.
10.4 g NaF x 1 mol NaF/42 g x 1 mol F/mol NaF = 0.248 moles F- ions (3 significant figures).
Naf is a Lewis acid because it is a compound formed by the combination of sodium (Na+) cation, which can act as an electron pair acceptor.
Yes, NaF is a salt composed of the elements sodium (Na) and fluorine (F). It is known as sodium fluoride.
The ionic compound formed when sodium (Na) and fluorine (F) react is sodium fluoride, with the chemical formula NaF. In this compound, sodium (Na) donates an electron to fluorine (F) to form an ionic bond between the positively charged Na+ ion and the negatively charged F- ion.
NaF is a salt, specifically an ionic compound formed from a metal (sodium) and a non-metal (fluorine). In solution, NaF dissociates into Na+ and F- ions.
Sodium- Na Fluorine- F Together- NaF
Fluoride ion is symbolised by F- .(Mind the spelling of flUOride, it is not flouride)
6
You think probable to sodium fluoride , NaF.
Na+F form NaF a ionic compound
Yes, fluorine and sodium form an ionic bond to create sodium fluoride. In this bond, sodium donates an electron to fluorine, leading to the formation of positively charged sodium ions and negatively charged fluoride ions that attract each other due to their opposite charges.