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That kind of loop is referred to as an Infinite Loop. It occurs when the exit conditions can never be met or when the programmer fails to supply an exit. For example: Do while (1>0) (that will loop forever because 1 is always greater than 0)
dim a(20) as integer dim i as integer dim n as integer private sub command_click() for i 1 to 20 Next i a(i) = inputbox ("enter any no.""no.""0") Next i for i = 1 to 20 print a(i) n=n/i if n mod 2 = 0 then Next i end if msgbox "even numbe"&even end if
#LMGTFY In this example, I have created an array of numbers called 'foobar', and while the variable 'sum' is less than 20, I will have the program continue to loop back and add the next number in the array sequence. #!usr/bin/env foobar = [1, 4, 7, 2, 9, 11, 0, 6, 5, 4, 16, 3] sum = 0 iteration = 0 while(sum < 20): sum += foobar[iteration] iteration += 1 print("Finished!")
A for loop works similarly to most programing languages. An example of a for loop isfor(i=0; i 3; y++) { }The declaration and initialization happens before anything else in a for loop. And whereas the other two parts-the boolean test and the iteration expression-will run with each iteration of the loop, the declaration and initialization happens just once, at the very beginning. You also must know that the scope of variables declared in the for loop ends with the for loop! The following demonstrates this:for (int x = 1; x < 2; x++) { System.out.println(x); // Legal } System.out.println(x); // Not Legal! x is now out of scope If you try to compile this, you'll get something like this: Test.java:19: cannot resolve symbol symbol : variable x location: class Test System.out.println(x); ^Basic for Loop: Conditional ExpressionThe next section that executes is the conditional expression, which (like all other conditional tests) must evaluate to a boolean value. You can have only one logical expression, but it can be very complex. Look out for code that uses logical expressions like this:for (int x = 0; ((((x < 10) && (y-- > 2)) | x == 3)); x++) { }The preceding code is legal, but the following is not:for (int x = 0; (x > 5), (y < 2); x++) { } // too many //expressions The compiler will let you know the problem: TestLong.java:20: ';' expected for (int x = 0; (x > 5), (y < 2); x++) { } ^ The rule to remember is this: You can have only one test expression. In other words, you can't use multiple tests separated by commas, even though the other two parts of a for statement can have multiple parts.Basic for Loop: Iteration ExpressionAfter each execution of the body of the for loop, the iteration expression is executed. This is where you get to say what you want to happen with each iteration of the loop. Remember that it always happens after the loop body runs! Look at the following:for (int x = 0; x < 1; x++) { // body code that doesn't change the value of x } The preceding loop executes just once. The first time into the loop x is set to 0, then x is tested to see if it's less than 1 (which it is), and then the body of the loop executes. After the body of the loop runs, the iteration expression runs, incrementing x by 1. Next, the conditional test is checked, and since the result is now false, execution jumps to below the for loop and continues on. Keep in mind that barring a forced exit, evaluating the iteration expression and then evaluating the conditional expression are always the last two things that happen in a for loop! Examples of forced exits include a break, a return, a System.exit(), or an exception, which will all cause a loop to terminate abruptly, without running the iteration expression. Look at the following code: static boolean doSomething() { for (int x = 0; x < 3; x++) { System.out.println("in for loop"); return true; } return true; } Running this code produces in for loop The statement only prints once, because a return causes execution to leave not just the current iteration of a loop, but the entire method. So the iteration expression never runs in that case. Basic for Loop: for Loop Issues None of the three sections of the for declaration are required! The following example is perfectly legal (although not necessarily good practice): for( ; ; ) { System.out.println("Inside an endless loop"); } In the preceding example, all the declaration parts are left out so the for loop will act like an endless loop. For the exam, it's important to know that with the absence of the initialization and increment sections, the loop will act like a while loop. The following example demonstrates how this is accomplished: int i = 0; for (;i
P=I^2*R. No. 8,000 watts.
Yes a 4 - 20 ma loop can be tested.
either a Boss RC-30 or if it's a slightly older model the Boss RC-20
For the First Time - The Script song - was created on 2010-08-20.
The Loop - 2008 was released on: USA: 20 July 2008 (48 Hour Film Project)
60
Making an infinite loop on everybody's edits is quite simple if you are familiar with computer software. The basic code to make the loop is " 10 PRINT "SPAM" 20 GOTO 10."
Take TX-105 EAST to LOOP-336 in Conroe. Turn left onto LOOP-336.Take LOOP-336 to I-45 NORTH.Take I-45 NORTH to I-20 WEST to FT. WORTH at EXIT 276A.Take I-20 WEST to Abilene.
When I have code that seems to endlessly loop, I always print out all variables in the loop that I can. I also assign count = 20 and count down to 0. Put count-- in the loop and just put: if(count == 0) break; That is the easiest thing to do.
Simply Ming - 2003 Chinese Rock Candy and Cranberries Script was released on: USA: 20 November 2010
20 Spot - 2006 was released on: USA: 7 October 2006 (Script-2-Screen Film Festival)
The Loop - 2006 Fatty 2-9 was released on: USA: 1 July 2007 Australia: 23 October 2008 Belgium: 20 February 2010
515 miles taking this route:Take U.S. 69 NORTH from Lufkin to I-20 WEST to DALLAS in Tyler. To bypass Rusk, take LOOP 343 WEST (turn left onto LOOP 343 WEST; then take LOOP 343 to where you cannot go any further, at FM-2972, turn left, and then take FM-2972 back to U.S. 69; turn left onto U.S. 69 NORTH). To bypass Tyler take LOOP 323 (turn left onto LOOP 323 WEST; take LOOP 323 back to U.S. 69. Turn left to continue on U.S. 69 NORTH).Take I-20 WEST to Midland.