To calculate the admittance if you are given the impedance, you take the inverse of the impedance ( that is 1/z).
I believe intrinsic impedance is more tied to the medium, thus is defined in terms of magnetic and electric permeability and electrical conductivity, while characteristic impedance is a "wider" look at the impedance. For example, you can calculate the intrinsic impedance of a 18 awg copper wire, or air, or a vacuum. If you wanted to use coax cable with an 18 awg core, you would be looking at the characteristic impedance, not the intrinsic impedance of the copper that will be carrying the waveform.
Because the saturation is not taken into consideration so the impedance calculated is more than the impedance that would have resulted once the saturation is taken into account.-- By Ankit(bigboss0086@gmail.com)
as i understand this impedance is something that impedes, or adds resistance or something like that. ( There are impedance bonds on the railroad to divide the track up into sections for signal purposes) by words, you see the connection with impede and impediment. the impedance, like resistance, would have to be a factor to be reckoned with. I am only familiar with Impedance bonds-they are laid horizontally under the track structure, and are part of the signal system.
Actually, its a matter of terminology... Impedance can be used in a DC circuit. We just call it resistance, however, transient analysis would imply a different notation. To be clear, impedance is normally used in AC circuits, and it is the electrical opposition to AC, taking into account not only voltage, but phase angle. In a DC circuit, impedance and resistance are the same thing, simply with a phase angle of zero.
10 megohms is the resistance through which 10 volts would push 10 microamps of current. Input impedance is the resistance seen by a signal source when connected to the input Often, this means there is a 10 megohm resistor in series with the input going to a virtual ground on an opamp circuit. 10 megohms is a common input impedance for a digital voltmeter.
Admittance is the reciprocal of impedance (1/Z) and is the vector sum of conductance (1/R) and susceptance (1/X). Admittance is used in solving parallel alternating-current circuits, because it avoids the need to vectorially add or subtract reciprocals, which would be the case if we were to use impedance, resistance, and reactance.
I believe intrinsic impedance is more tied to the medium, thus is defined in terms of magnetic and electric permeability and electrical conductivity, while characteristic impedance is a "wider" look at the impedance. For example, you can calculate the intrinsic impedance of a 18 awg copper wire, or air, or a vacuum. If you wanted to use coax cable with an 18 awg core, you would be looking at the characteristic impedance, not the intrinsic impedance of the copper that will be carrying the waveform.
In that case, it would be good to know WHAT is given. If NOTHING is given, you really can't calculate.
You would have to know (a) what you are actually supposed to calculate, and (b) what ARE you given, not just what you AREN'T given. If no data is known, you'll have to do some measurements.
I would install an AAV if
Obviously it's not infinite impedance--that would mean it soaks up all the voltage. It can't be zero impedance either...that would be a superconductor, and there aren't many of those around. Voltage sources have impedance, but it's not infinite. Sometimes the impedance of the source is critical--radio frequency amplifiers have to be impedance matched to their transmitting antennas if you don't want to burn them out.
I guess that would depend on what you want to calculate (the charge? the velocity? the average energy of the charges?), and what information is given.
The real impedance is the resistance in ohms more 20%. A coil resistance of 6,7 ohms X 1.20 = an impedance of 8.04 ohms. If the voice-coil had exactly 8 ohms, the impedance would be 9.6 ohms and the sound would be unclear, tending to more basses.
no. an apology would mean admittance of guilt/complicity.
The best way to answer this question might be to consider the consequences if the input impedance was low: with a low input impedance, (signifficant) current would start flowing, and the amplifier would draw energy from the signal sources. None of the typical signal sources is designed to deliver energy on its outputs (after all, this is where the amplifier itself comes in). It is certainly possible to think that some of these sources might be changed to deliver some energy, but this is not the case with present-time tuners, CD players, microphones, and so forth. Assuming that the energy supply was not the issue, just to ponder this theoretical scenario a little further, the fact that current would flow from the source to the amplifier would also make the signal more vulnerable to the characteristics of the cable that connects the two. The high impedance of an amplifier input draws no energy, thereby avoiding these issues. It is the amplifier's task to convert a very low energy, voltage-driven signal into an higher energy output signal (driving the speakers which themselves have a very low impedance). ---- The way I typically think about this is to consider connecting a load to a Thevenin equivalent circuit [1]. The voltage across the load is given by the voltage divider formula (Vload = Vsrc * Rload/(Rload+Rthevenin)). If there is a very low load impedance--this means the amplifier has a very low input impedance--most of the source voltage will drop over the Thevenin equivalent resistance. With a very high input impedance, however, the majority of the signal voltage will be transferred from the source to the load because in the above equation, if Rload >> Rthevenin, Vload is approximately equal to Vsrc. if an amplifier has low impedance input the f/b must be low impedance also which make it in practical to use. The hi impedance of a typical amplifier is because the input is one two diodes basically operating on it exponential curve. Making it virtual the same as the other diode. for a differential amplifier. Boltzmann constant will define the impedance of a single diode.
I would guess 250 grams.
Because the saturation is not taken into consideration so the impedance calculated is more than the impedance that would have resulted once the saturation is taken into account.-- By Ankit(bigboss0086@gmail.com)