String passage= new String("blah blah blah");
int vowelSum=0;
for(int i=0;i<passage.length();i++)
if(passage.charAt(i)=='a' passage.charAt(i)=='e' ...etc....
vowelSum+=1;
System.out.println(vowelSum);
That is a basic idea and in no way the best possible way to do it.
JBuck
Hello
By preparing test cases we can test an algorithm. The algorithm is tested with each test case.
the number of steps of an algorithm will be countable and finite.
algorithm to convert a number representing radix r1 to radix r2
If the average of 5 numbers is 23 and the range is 10, what are the 5 numbers?
Dijkstra's original algorithm (published in 1959) has a time-complexity of O(N*N), where N is the number of nodes.
algorithm is a way to solve your problem
By preparing test cases we can test an algorithm. The algorithm is tested with each test case.
Multiply the average by the number of terms.
You calculate average change in inventory by dividing the turnover by how many times it has turned over. The number you get is the average.
Use the link provided to University of Arizona math page where the algorithm is explained.
1.Start Algorithm 2.Enter first number 3.Enter second number 4.Enter third number 5.Enter fourth number 6.Enter fifth number 7.Add five number 8.display five number / 2 9.Display result 10.End Algorithm
it is obvious the average is not by just one person it is by a group of people so you need to ask a group of people what their IQ is and add them all up then divide them by the number you used
If you want to calculate the average of a list of numbers, add the numbers together and divide it by the number of numbers.
The first step is to convert the logical device number into a physical address. Then you must schedule an IO request. You improve the seek time by testing the IO numbers to see what gives the best results.
(sum of data)/number of data
to calculate your average handling time: average talk time+after callwork+hold time divided by the number of calls
the number of steps of an algorithm will be countable and finite.