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Let's say we're talking about red flowers (red=dominant, R allele) vs white flowers (white=recessive, r allele) If you cross two homozygous red flowers, RR x RR, you can only get RR offspring, or all red flowers. RR=genotype (what alleles, or genes, they have), red=phenotype (what they look like) To make the Punnett square, draw a 4-box diagram on a piece of paper by drawing a diagonal line and then a horizontal line halfway down so you get 4 squares. On the top of the box, put R R and along the left side, put R and then another R under it. To fill in the boxes for the Punnett square, cross the top left-hand gene (R) with the top gene on the left-hand side. You'll get RR. Do the same for the top right-hand gene (R) and the top gene on the side. You'll also get RR. Cross the bottom R with the left gene on the top (R) and the right gene on the top. All combinations will be RR in this example. If you had a red flower that had a homozygous genotype (RR) with a white flower, also homozygous (rr), the results are more interesting. When you draw your Punnett square, you'll see that you get one RR combination, two Rr combinations and one rr combination. This means that the F1 generation (offspring) will be: 25% homozygous red (RR) 50% heterozygous red (Rr) 25% homozygous white (rr) Put another way, you'll have one white flower and three red flowers, and two of those red flowers carry a gene for white which is not expressed because it is recessive.
the probabiltiy it will be black is if the grandparents are white or if the relitives that are 1st might be the soulution
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The offspring would be 100% pink snapdragons.
All the offspring were purple because Mendel was dealing with simple genetic dominance. The purple true breeding parent was homozygous dominant and the true breeding white parent was homozygous recessive. When those two are crossed they create only heterozygous offspring (look up a punnett) and since this is simple dominance those heterozygous will show the phenotype of the dominant allele which is purple.
white
The offspring produced is dependent on chances. We can figure out the chances of the kind of offspring such a cross will get by using a Punnett square. Unfortunately the WYSIWYG format on this site will not allow for such a square, so we will give the ratio, the genotypic and phenotypic percentages that such a cross will receive. Let R = red, W = white and RW = roan. Roan cow (RW) x White bull (WW) Offspring: 2 RW : 2 WW Genotypic ratio: 50% roan and 50% white Phenotypic ratio: Same as above. Thus, the offspring of a roan cow crossed with a white bull (presumably of the same breed, being Shorthorn), may come out as white or roan. There is a 50% chance that either will occur.
Punnett Squares are useful because they allow you to see the chance of what genes will be handed down to the offspring. They are a quick and easy way to determine the chance of a offspring having a certain characteristic
A punnett square looks like this. Lets say that you had 2 flowers, and you wanted to find the likelihood that their offspring would be purple. Purple is dominant over white. You have one pure purple plant, (PP), and one hybrid purple plant, (Pp). The big P stands for purple, and the little p stands for white. You take the PP and put it on the top, one P over each of the top squares. Then you take the Pp and put each p on one of the side squares. You take one letter from each part of the square, so your four possibilities would be PP, PP, Pp, and Pp. There is no way that the plant could be white.
So I took the worksheet and found that in Punnett Square A (if you have the same worksheet) It has the pairs BB, Bb, Bb, and bb. B= black and b= white. The probablility of a black guinea pig is likely and white is unlikely since there is only 1 trait with 2 recessive alleles.
Let's say we're talking about red flowers (red=dominant, R allele) vs white flowers (white=recessive, r allele) If you cross two homozygous red flowers, RR x RR, you can only get RR offspring, or all red flowers. RR=genotype (what alleles, or genes, they have), red=phenotype (what they look like) To make the Punnett square, draw a 4-box diagram on a piece of paper by drawing a diagonal line and then a horizontal line halfway down so you get 4 squares. On the top of the box, put R R and along the left side, put R and then another R under it. To fill in the boxes for the Punnett square, cross the top left-hand gene (R) with the top gene on the left-hand side. You'll get RR. Do the same for the top right-hand gene (R) and the top gene on the side. You'll also get RR. Cross the bottom R with the left gene on the top (R) and the right gene on the top. All combinations will be RR in this example. If you had a red flower that had a homozygous genotype (RR) with a white flower, also homozygous (rr), the results are more interesting. When you draw your Punnett square, you'll see that you get one RR combination, two Rr combinations and one rr combination. This means that the F1 generation (offspring) will be: 25% homozygous red (RR) 50% heterozygous red (Rr) 25% homozygous white (rr) Put another way, you'll have one white flower and three red flowers, and two of those red flowers carry a gene for white which is not expressed because it is recessive.
the probabiltiy it will be black is if the grandparents are white or if the relitives that are 1st might be the soulution
B = blackb = whiteBb x Bb. make the punnett square. Being heterzygous, they would never have 20 white rabbits. a few at the most.
The question depends on what the offspring is of!
No, not always. The offspring can be white, black, black and white or shades of both.
Usually between two and ten pups, which grow in eggs and hatch inside the mother.
i looked this up along time ago but i think i remember i think its 3 or 4