the man has huntingtons disease
In this situation, there is a 50% chance of inheriting the disease.
Firstly, if the condition is recessive, both the man and the child with the condition must have the genotype tt. The mother must have the genotype Tt. This is because if she had TT, all of the children would be Tt and not have the condition. If she were tt, she would have the condition as well. Therefore if the father has tt and the mother has Tt, the other 3 children who do not have the condition must all have the genotype Tt. So: Mother - Tt Father - tt Affected child - tt Other children - Tt
The man has Huntington's disease
With an autosomal recessive inheritance pattern, a person needs to have 2 copies of a gene change to have the condition. In most cases, people with an autosomal recessive condition get one gene change from the mother and one gene change from the father.The parents of a person with an autosomal recessive condition may not have the condition themselves, since each parent only needs to have one copy of the gene change. People with one copy of the gene change are called carriers, who do not have the condition, but are more likely to have children with the condition. Other family members (uncles, aunts, brothers, cousins, etc) may also be carriers.
Yes. At least two possibly three. Two from his first wife.
both parents could be A heterozygous or one A heterozygous and the other O
There is 50% that children will be of negative blood type if parents are heterozygous positive. 25% if one parent is homozygous and other heterozygous. 0% if both homozygous.
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
no because his children are heterozygous not homozygous, which is the prerequisite for being purebred
1/8 or 12.5%
Hemochromatosis can skip generations because it is an autosomal recessive genetic disorder. This means that an individual can carry a gene for hemochromatosis without showing symptoms, and it may not be expressed in every generation. The risk of developing the condition depends on inheriting two copies of the mutated gene, one from each parent.
Sex linked traits are of 2 types X linked ,which are transmitted from maternal grand parent to maternal grand children through carrier daughter , and Y linked are transmitted from father to son , whiles autosomal genes transmit equally among children .