The mass of sulfur is 6,118 g.
60 grams.
7
36 grams
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
6,5 grams of sulfur S are equal to 0,203 moles.
Al2S3
Formation of lead (II) sulphide; not all the sulfur reacted.
what happens if 5.00 grams of sulfur is reacted with 10.00 grams of lead producting lead sulfide
From the periodic table, calcium has a molar mass of 40.078g/mol and sulfur has a molar mass of 32.065g/mol. The formula for compound formed from calcium and sulfur, calcium sulfide is CaS. The molar mass of CaS is 72.143. So, if you round the numbers, 40g of Ca + 32g of S will produce 72g of CaS.
60 grams.
This is a limiting reagent stoichiometry problem, so that means you have to run the calculations twice; once for 5 grams of silver and once for 5 grams of sulfur. When you do this, you'll find that for 5 grams of silver (and an excess of sulfur) you would get 5.68 g of product, and for 5 grams of sulfur (and an excess of silver) you would get 39.52 g of product. So, you have to go with the less of the two amounts, because that's the most you can ever produce. So the answer is 5.68 g of silver(I) sulfide, with silver being the limiting reagent.
7
36 grams
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
About 23.2 grams of Sulfur.
53,7 grams of sulfur is equivalent to 1,675 moles.
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------