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3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
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∙ 6y ago
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How many atoms are in 175 grams of calcium?
Quite a few! 175 grams calcium (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca) = 2.63 X 10^24 atoms of calcium -------------------------------------------
How many atoms of zinc are there in 135 gms?
135 grams zinc (1 mole Zn/65.41 grams)(6.022 X 10^23/1mole Zn) = 1.24 X 10^24 atoms of zinc
What is the atomic mass for cobalt?
57 grams Florine (1 mole F/19.00 grams)(6.022 X 10^23/1 mole F) = 1.8066 X 10^24 atoms Florine 1.8066 X 10^24 atoms (1 mole Co/6.022 X 10^23)(58.93 grams/1 mole Co) = 176.79 grams of cobalt ( sigi figi might be 180 grams )
What is the mass in grams of 6.022 x 1023 N atoms of mass 13.01 amu?
13.2 atomic mass units = 2.1919113 × 10-23 grams. (1 atomic mass unit = 1.66053886 × 10-24 grams).
How many mols of sodium are present in 45.48 g of sodium?
# of moles = Mass÷ Formula weight Example: 6 grams of Carbon atoms Carbon has an atomic mass of 12 grams so according to the Equation # of moles = 6÷ 12 = 0.5 moles For a compound such as CO2 , Formula weight = ( 1 mole of carbon atom weighs 12 grams + 2 moles of oxygen atoms weighs 32 grams ) 44 grams. Example: 24 grams of carbon dioxide = 24÷ 44 = 0.5454 moles So for sodium, # of moles = 45.48 g ÷ 22.99g/mole = moles You divide!
What is the mass of 3.09X1024 atoms of sulfur in grams?
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
How many atoms are there in 72.0 g of sulfur?
72.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.35 X 10^24 atoms of sulfur
How many sulfur atoms are in 78.4 grams of sulfur?
I rounded up to 1.47 X 10^24 atoms of Sulfur in 78.4 grams Sulfur78.4 grams X (1 mole S/32.07 g S) X (6.02 X 10^23 atoms S/ 1 mole) = 1.472 X 10^24 atomTaking significant digits into account (3 sig. figs.), I get 1.47 X 10^24 atoms S
How many grams of sulfur trioxide are present in 4.136 mol?
2.408 x 10^24 atoms.
How many atoms are there in 128.4 grams of sulfur?
128.4/32=4.0125mol Atoms=4.0125 x 6.022 x 10^23=2.4163 x 10^24 atoms
How many sulfur atoms are there in 4.3 mole of sulfur?
2.6*10^24
How many atoms are in 195 grams of calcium?
2.936*10^24 atoms....
What is the empirical formula for 16 grams of sulfur reacting with 24 grams of oxygen?
To find empirical formulas, masses of elemental reactants must be changed to gram atoms by dividing the mass by the gram atomic masses of each element. Thus, 16 grams of sulfur constitutes 16/32.06 or 0.50 mole to the justified number of significant digits, and 24 grams of oxygen constitutes 24/15.9994 or 1.50 moles of oxygen to the justified number of significant digits. Therefore, the atomic ratio of oxygen to sulfur in the compound is 1.50/0.50 or 3, and the empirical formula is SO3.
How many atoms are in 5 moles of sulfur?
multiply 5 with 6.02x10x23 and the answer will be 3.01x10
How many sulfur atoms are there in 3.1 mole of sulfur?
To find this, you simply multiply the number of moles by avogadro's number which is 6.22 X 10^23. 3.1 x 6.022x10^23 = 1.9 x 10^24 atoms of sulfur.
How many atoms of sulfur are there in 2 mol of sulfur?
For this you need the atomic mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.4 mole S × (32.1 grams) = 77.0 grams S
How do you convert 3.2 moles of sulfur to atoms?
Simply multiply 3.2mol(6.022x10^23)= 1.93x10^24
