For this you need the Atomic Mass of S. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
2.4 mole S × (32.1 grams) = 77.0 grams S
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
To find the number of atoms in 64 g of sulfur, you need to first determine the molar mass of sulfur (S), which is approximately 32.06 g/mol. Next, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, 64 g of sulfur contains approximately 1.2 x 10^24 atoms.
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
Each sulfur atom in an S8 molecule is bonded to two other sulfur atoms, forming a ring structure with a total of 8 sulfur atoms.
The formula shows that each mol contains 2 hydrogen atoms, and, for any substance, the number molecule per mole is Avogadro's Number. Therefore, 2 X 0.1262 X 6.022 X 1023 or about 1.520 X 1023 hydrogen atoms, to the justified number of significant digits.
To calculate the number of atoms in 64 grams of sulfur, you first need to determine the molar mass of sulfur (32 g/mol). Then, you divide the given mass by the molar mass to find the number of moles (64 g / 32 g/mol = 2 mol). Finally, you use Avogadro's number (6.022 x 10^23) to find the number of atoms in 2 moles of sulfur, which would be 2 mol x 6.022 x 10^23 atoms/mol.
2(6.02 x 10^23) atoms
Assuming you are talking about pure sulfer. Atomic weight of Sulfer is : 32.07g/mol 100g / 32.07 g/mol = 3.06 mol (rounded to nearest 2 decimal place) 1 mol = 6.022 141 79 × 1023 atoms. 3.06 X 6.022 141 79 × 1023 = 1.82 X 10^24 atoms
To find the number of atoms in 64g of sulfur, you need to divide the given mass by the molar mass of sulfur, which is approximately 32 g/mol. This gives you 2 moles of sulfur. One mole of sulfur contains 6.022 x 10^23 atoms, so 2 moles would have 1.2044 x 10^24 atoms.
To find the number of atoms in 64 g of sulfur, you need to first determine the molar mass of sulfur (S), which is approximately 32.06 g/mol. Next, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, 64 g of sulfur contains approximately 1.2 x 10^24 atoms.
One molecule of sulfuric acid, H2SO4, contains 7 atoms (2 hydrogen, 1 sulfur, and 4 oxygen). Therefore, in 1.5 mol of sulfuric acid, there would be 1.5 x 6.022 x 10^23 atoms, which is approximately 9.033 x 10^23 atoms.
1 mol S2 * (2 (32.07) g S2/mol S2) = 64.14 g S2
1 mole S = 32.065g 32g S x 1mol/32.065g = 1.0mol S (rounded to 2 significant figures)
The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%
A thiosulfate ion (S2O3^2-) consists of 3 oxygen atoms, 1 sulfur atom, and 2 hydrogen atoms for a total of 6 atoms.
To calculate the number of atoms in 64 g of sulfur, you need to determine the number of moles first. The molar mass of sulfur is approximately 32 g/mol. Thus, 64 g of sulfur is equal to 2 moles. Avogadro's number states that there are 6.022 x 10^23 atoms in one mole of an element, so there would be approximately 1.2044 x 10^24 atoms in 64 g of sulfur.
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------