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If A flask contains 440 mol of liquid bromine Determine the number of bromine molecules in the flask?
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∙ 14y ago
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
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∙ 14y ago
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Determine the number of bromine molecules present in the flask containing 0.120 of liquid bromine?
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
A flask contains 0.380 mol of liquid bromine Determine the number of bromine molecules present in the flask?
2,288.1023 molecules
A flask contains 0.500 of liquid bromine Determine the number of bromine molecules present in the flask?
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
A flask contains 0.290 mol of liquid bromine Determine the number of bromine molecules present in the flask?
.290 x (6.022 x 10^23) = 1.75 x 10^23
A flask contains 0.270 of liquid bromine Determine the number of bromine molecules present in the flask?
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
Determine the number of bromine molecules present in the flask containing 0.120 of liquid bromine?
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
A flask contains 0.380 mol of liquid bromine Determine the number of bromine molecules present in the flask?
2,288.1023 molecules
A flask contains 0.500 of liquid bromine Determine the number of bromine molecules present in the flask?
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
A flask contains 0.290 mol of liquid bromine Determine the number of bromine molecules present in the flask?
.290 x (6.022 x 10^23) = 1.75 x 10^23
A flask contains 0.270 of liquid bromine Determine the number of bromine molecules present in the flask?
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
A flask contains 0.310 of liquid bromine Determine the number of bromine molecules present in the flask?
.310 MOLES 6.022*(10^23 ) molecules --------------- times ------------------------------------ = 1.8668 * 10^23 molecules 1 mole because there are 3 sig figs the answer should reflect that number. so the answer is 1.87 * 10^23 molecules
Which diotomic molecules are a liquid at room temperature?
Bromine, Br2, is a diatomic molecule that is liquid.
What group contains an element that is a liquid at room temperature?
Bromine
What element's atoms form diatomic molecules as a liquid?
Bromine is the only element that is liquid and forms diatomic molecules Br2. Mercury is also an element and is liquid but is monoatomic.
What simple experiment can be used to determine if a liquid compound contains polar molecules?
Thin Layer Chromatography (TLC) procedure can be used
Which element on the periodic table is a nonmetallic liquid at STP?
Bromine, group 17; Mercury, group 12. Both are liquids at STP
What is the nonmetal liquid on the periodic table?
Bromine is non metal which is liquid.It is halogen.It belongs to group-17.There are only two elements in the periodic table that are non metals. They are bromine and mercury. From those, bromine is the only non metal.There are only two liquid elements in the periodic table. The only non metal liquid is Bromine. Bromine stays as a diatomic molecules.
