011.1
11.1
Internal resistance is approximately equal to 94.667
No, it is desirable for a battery to have a low internal resistance.
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
There is internal resistance in a battery because a battery is not an ideal voltage source. It may be close, but it is not ideal. As a result, analytically, there will be some series resistance, resistance which places a limit on the maximum current that the battery can provide. While no battery is ideal, most are sufficiently ideal to not require any consideration of the internal resistance. If your circuit is dependent on the internal resistance of a battery, then it is probably not well suited for that application.
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
Internal resistance is approximately equal to 94.667
No, it is desirable for a battery to have a low internal resistance.
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
There is internal resistance in a battery because a battery is not an ideal voltage source. It may be close, but it is not ideal. As a result, analytically, there will be some series resistance, resistance which places a limit on the maximum current that the battery can provide. While no battery is ideal, most are sufficiently ideal to not require any consideration of the internal resistance. If your circuit is dependent on the internal resistance of a battery, then it is probably not well suited for that application.
Yes
A loose battery terminal will cause intermittent power supply, high resistance and heating. A high resistance will cause a voltage drop, as more current is drawn from it.
That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.
You have to imagine the internal resistance as being in parallel with any load you connect. You get the maximum possible current when the load is zero. In this case, just apply Ohm's Law. That is, divide the voltage by the internal resistance.
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
4.8 / (1.2 + R) = 34.8 = 3 (1.2 + R)4.8 = 3.6 + 3R1.2 = 3R0.4 ohm = R
"The potential difference between the terminals of a battery will equal the emf of the battery when there is no current in the battery. At this time, the current though, and hence the potential drop across the internal resistance is zero. This only happens when there is no load placed on the battery-that includes measuring the potential difference with a voltmeter! The terminal voltage will exceed the emf of the battery when current is driven backward through the battery, in at its positive terminal and out at its negative terminal." Raheel Ahmed Quaid i Azam University Islamabd Physics Dept
It causes the battery's voltage to drop when a current is drawn from it.