This depends on the type of condition that Tay-Sachs is.
Seeing that Tay-Sachs can be "carried" and not expressed, it is possible that it is a recessive condition. As such, the husband must be heterozygous, with an allele for Tay-Sachs, and a normal one.
Since his wife is homozygous normal, and taking into account the fact that one allele is taken from each parent, it is not possible for the children to have Tay-Sachs. However, the children may be carriers.
Note: This answer assumes that the gene for Tay-Sachs works in isolation.
Edit: this is a valid answer, it may have been misunderstood by the questioner. Since the disease is recessive, a 'carrier' like the husband would be heterozygous (carrying one allele for Tay Sachs disease and the other allele is 'normal'). If you could be sure that the wife is definitely homozygous 'normal' (ie both alleles are 'normal'), and that the gene works in isolation, then the first answerer is right, there is no chance that a child would have Tay Sachs disease but there would be a 50% chance that the child would be a carrier . However, unless the wife has been definitively genotyped for this disease, there is always the chance that she is a carrier also which could result in children with Tay Sachs disease.
It is 50% for the children to get the Tay-Sachs from the father, because the mother doesn't have any disease, do it is half.
This answer is satifactory to anyone who knows anything about Biology. The simple answer is none of the children will have it but there is a 50% chance of them being carriers. As stated above.
if someone is a Heterozygous carrier of Tay-Sachs they would have to be Tt. Because TT is Homozygous.
carrier
The carrier must be Homozygous because if he were hetero it must be Hh and the dominant gene is expressed but homozygous gives them the possibility of hh (only a carrier) or HH (definitely a carrier) Don't totally understand the previous answer; however, I understand the question to mean that you want to know if you are homozygous or heterozygous for a certain trait. If you express a recessive phenotype, that is you have blue eyes for example, you are definitely homozygous for that trait. If one of your parents has a recessive trait, like blue eyes, and the other parent expresses a dominant trait, like brown eyes, AND if you have brown eyes, you can be sure that you are heterozygous. Otherwise it is impossible to tell until you have children. Then you can work backwards from you and your spouse, look at their parents and your parents and then figure the only possible way all those conditions could exist is if you are heterozygous or if you are homozygous for that trait.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
An X linked carrier is one who carries a mutation in a gene found on the X sex chromosome. A carrier of the trait doesn't display phenotypic symptoms of the disease or mutation but can transfer the mutation in that gene to their offspring (ex: the carrier of a premutation that when transferred to the offspring via the X chromosome will cause the full mutation associated with that gene). A person could be a homozygous carrier if for instance, she were female (two X chromosomes) and carried the premutation associated with the disease. Some diseases need both alleles of the gene to be mutated. If only one allele is mutated (heterozygote) that person may be a carrier for that mutation and can thus pass on that mutation to their children.
No, because he or she cannot pass the gene on to his or her offspring (because he or she does not have a copy of the gene).
No, because he or she cannot pass the gene on to his or her offspring (because he or she does not have a copy of the gene).
Is a carrier of that disease. Aa a being the recessive gene
50%
The chances are one half. You will most likley have 2 children without the gene, and 2 with one gene. Since the normal parent has the dominate allele, the Cystic Fiborisis will not be present.
No he did not have children even though he had 3 wives.
A carrier.