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It requires 6 bits to address 64 words. It does not matter what the word size is.
address space=24bits => (2 Power 24)=16M words
All else being equal, it can address 2^36 words of memory, or 68,719,476,736 words (64 gigawords). If it's a "modern" computer, it probably has 8-bit words, so that's 64 gigabytes. If the word size is also 36 bits (as was common in computers in the '50s and '60s), it can address 2,473,901,162,496 bits, or 309,237,645,312 eight-bit bytes (288 gigabytes).
In other words, MAR holds the memory location of data that needs to be accessed. When reading from memory, data addressed by MAR is fed into the MDR (memory data register) and then used by the CPU. When writing to memory, the CPU writes data from MDR to the memory location whose address is stored in MAR. The Memory Address Register is half of a minimal interface between a microprogram and computer storage. The other half is a memory data register. Far more complex memory interfaces exist, but this is the least that can work.
It doesn’t address any of those things. It states a philosophy of government and the need for change.
The memory address space is 64 MB, which means 226. However, each word is 4 bytes, which means that you have 224 words. This means you need log2 224 or 24 bits, to address each word.
The words gift registry means that someone has selected certain items that they would like to receive as gifts, from that given store. This registry allows guests to give something that will be wanted and used by those who receive it.
consider a RAM of 64 words with a size of 16 bits.Assume that this memory have a cache memory of 8 Blocks with block size of 32 bits.Draw a diagram to show the address mapping of RAM and Cache, if 4-way set associative memory scheme is used.
If you are addressing bytes, then 512K words (16 bit words) requires 20 address lines.I gave that answer because the question was categorized 8086/8088. If you are addressing words, then the answer is 19 address lines.
We should never forget it.
To put it in simple and non technical words: The delay time between a memory controller try to access a particular memory address and the time this data is ready in the output pin's. measure unit is usually Cycles.A Simple example: a memory that works on 100Hz, 1 CL=0.01seconds. Basically, the lesser the better, but depends on the memory freq.
semantic memory