I'm not quite sure of my ground here, but here are my thoughts: Data: equatorial radius of the earth (r) = 6378137 m. equatorial gravitational field strength (g) = 9.78 Nkg-1 In order for the rotation of the earth to perfectly cancel weight, the gravitational field strength g should equal the centripetal acceleration, a. a = w2r where w is the Earth's angular velocity. If T is the duration of a day in seconds, then we can substitute w = 2 x pi / T giving a = 4pi2r / T2 Equating a to g: 4pi2r / T2 = 9.78 Rearranging to find T: T = sqrt(4pi2r / 9.78) Substituting pi = 3.1415... and r = 6378137 T = 5074 seconds (nearest second) which is 1 hour, 24 minutes and 34 seconds, or about 17 times shorter than an ordinary day.
The length of the Earth's equator is 12,756,000 meters."The Solar System", Roman Smoluchowski, Scientific American Library, 1983, page 164
Day and night are of equal length throughout the year at the equator.
It doesn't work that way. There is no height at which you magically become weightless.
it is 3,897,769,560.5647393748 ft around the earth According to WGS-84, IAU 1976 and 2000, the exact length of the equator to the nearest whole number is 24,901 miles, or 40075 kilometers.
The Equator is the line of latitude located at 0 degrees that represents a line on the Earth's surface equidistant from the North Pole and South Pole. Earth is widest at the equator which is its circumference so this is the longest line of latitude with a length of 40,075.16 km (24,901.55 mi).
For small swings of a mass suspended on a weightless string, the period is given by T = 2 pi sqrt (a/g) where a is the length of the pendulum and g is the acceleration due to gravity.
The length of the Earth's equator is 12,756,000 meters."The Solar System", Roman Smoluchowski, Scientific American Library, 1983, page 164
The length of the Earth's equator is 12,756,000 meters."The Solar System", Roman Smoluchowski, Scientific American Library, 1983, page 164
That would be the equator.
The person in space exerts a force of 850 N on the earth. The fact that the person is weightless has no bearing on this question. Ever since Newton enunciated his three laws of motion we have known that action and reaction are equal and opposite. If the earth pulls him with 850 N, then he pulls the earth with 850 n.
Originally earth was a weightless liquid blob, which will default to a spherical shape, add to this the rotation and centripetal swelling at the equator which flattens the poles, then after cooling and solidifying, this pretty much is earth today.
not on earth but it can be simulated underwater, in aircraft, you can be weightless in outer space
The equator.
The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.The earth's equator is approximately 40,075 kilometres. There is no exact value because, amongst other things, the equator is not static: it moves with shifts in the axis of the earth's rotation.However, using calculus, it is possible to show that the length of the string would need to be 2*pi inches = 6.3 inches greater than the length of the equator measured in inches. Given the variability in measuring the earth's equator, that difference will not be identifiable.
Yes. In fact they would feel weightless.
The length of Earth's equator is about 38,622 kilometres.
Day and night are of equal length throughout the year at the equator.