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If the frequency of the p allele is .63 in the population then what is the frequency of the q allele?
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Red-green colour blindness in human is caused by an X-linked recessive allele if the trait occur in 4 of the males in a population at Hardy-Weinberg equilibriumthen the frequency of this allele is?
If 4% of males in a population have red-green color blindness, then the allelic frequency is 4% in males and in females. If mating is random, then in females, 92.16% do not carry the allele on either X chromosome, 7.68% carry the allele on one X chromosome, and 0.16% carry the allele on both X chromosomes. We have the dominant allele with frequency p and the recessive allele with frequency q, so 0.9216 + 0.0768 + 0.0016 = p^2 + 2pq + q^2 = (p + q)^2 = (0.96 + 0.04)^2
What do mutations do to alleles?
Generally, gene frequency will not change significantly unless the mutation is successful and advantageous enough that it is heavily selected in the population. Since most mutations result in failure of the organism to thrive (death, reproductive failure, etc.) they have little or no effect on a population's gene frequencies. Even if the mutation has no apparent detrimental effects it will, itself remain in the population at a low frequency unless it enhances the organism's ability to reproduce within the population.
What does the q represent in hardy-weinberg equation?
It depends on what you make p equal to. P is usually the frequency of the dominant allele, which makes q the frequency of the recessive allele, but they can be switched. As long as p is one frequency and q is the other, the formula will work. So if you have the dominant allele frequency (A) =.6 then the recessive allele frequency (a) =.4, because p+q=1 When you plug the frequencies into the hardy-weinberg equation p^2 +2(p)(q) + (q)^2 = 1 then you have (0.6)^2 + 2(0.4)(0.6) + (0.4)^2 = 1 (0.6)^2 = 0.36 which is the frequency of dominant homozygotes 2(0.4)(0.6)=0.48 which is the frequency of heterozygotes (0.)^2 = 0.16 which is the frequency of recessive homozygotes If you have a population of 100 people, these frequencies would mean that: 36 people would be AA 48 people would be Aa 16 people would be aa Which would mean that 36+48=84 people would exhibit the dominant trait and 16 people would show the recessive trait.
What is the answer for the Hardy Weinberg equation?
p2 + 2pq + q2 = 1 and p + q = 1p = frequency of the dominant allele in the populationq = frequency of the recessive allele in the populationp2 = percentage of homozygous dominant individualsq2 = percentage of homozygous recessive individuals2pq = percentage of heterozygous individuals
What effect does nonrandom matinghave on the frequency of alleles in a population?
Nonrandom mating means that, for some reason, there is some selection occurring in mating, meaning that some organisms are more desirable to mate with than others. Logically, this is because of some certain characteristic or trait that is more desirable for organisms of the next generation to have. Thus, organisms with this trait or more likely to mate and produce offspring with similar characteristics, altering allele frequency so there are more of the "desirable" allele in the next generation and fewer of the "undesirable," as that allele was not passed on. For example, let's look at a hypothetical population or an imaginary animal. Let's pretend that the females are more attracted to males with brightly coloured feathers than those without pigment, and there are two alleles for the same gene that decide whether or not each organism is brightly coloured or not. Though non-random mating would mean that the allele frequency for each variation stayed the same through the generations, if more females mate with the brightly coloured males, fewer mate with the non-pigmented males. These males die without passing along the allele for non-pigmented feathers, decreasing its frequency. At the same time, the brightly coloured males pass on their allele to many offspring, effectively increasing the allele frequency. This process of choosing a more desirable trait makes rating nonrandom and changes allele frequency.
Red-green colour blindness in human is caused by an X-linked recessive allele if the trait occur in 4 of the males in a population at Hardy-Weinberg equilibriumthen the frequency of this allele is?
If 4% of males in a population have red-green color blindness, then the allelic frequency is 4% in males and in females. If mating is random, then in females, 92.16% do not carry the allele on either X chromosome, 7.68% carry the allele on one X chromosome, and 0.16% carry the allele on both X chromosomes. We have the dominant allele with frequency p and the recessive allele with frequency q, so 0.9216 + 0.0768 + 0.0016 = p^2 + 2pq + q^2 = (p + q)^2 = (0.96 + 0.04)^2
What is the frequency of genotype AA if the frequencies of AA?
If the frequency of genotype AA is p^2, where p is the frequency of allele A, then the frequency of genotype AA would be p^2.
The Hardy-Weinberg principle is written what does the p represent?
p is the value of an allele frequency.
The Hardy-Weinberg formula and what each of the terms mean?
formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency
What is meamt by allele frequency?
The incidence of an allele within the population compared to all other alleles. The Hardy-Weinberg equation is useful to calculate this- p2 + 2pq + q2 = 1 where p is incidence of the dominant allele and q is the incidence of the recessive allele where there are only two versions. If blue eyes is recessive and 0.36, then q2 = 0.36 so therefore q= 0.6 so the frequency of the blue eye allele is 60%.
How is an allele frequency different than a genotype?
The frequency of an allele is the total number of alleles of that type in a population where as genotype is the alleles present in all individuals in a population. The Hardy-Weinburg principle and its associated equations allow simple calculations of gene frequency. The basic equation is p+q=1: where p and q represent the dominant and recessive alleles. It is also simple to substitute the letters associated with the alleles you are dealing with for p and q. For example: If dealing green versus yellow where green is dominant and yellow is recessive green would be G and yellow would be g. Therefore G+g=1. In this example 40% of the population is yellow or 0.4. This means that g2 = 0.4 and this makes g = 0.63 (rounded off). Therefore 63 percent of the alleles for this trait are for yellow and 37 percent of the alleles in the population are for green. Since G+g=1 we know that 1.0-0.63=0.37 which is G. So 40 percent of the population is gg, it's genotype, but the frequency of the g allele is 63 percent' Likewise 60 percent of the population is GG or Gg but the frequency of G is 37 percent. There is a secondary equation that allows the calculation of percentages of GG and Gg as well with GG at 13.7% of the population and Gg at approximately 46.6% of the population. gg would be at 39.7%
What do mutations do to alleles?
Generally, gene frequency will not change significantly unless the mutation is successful and advantageous enough that it is heavily selected in the population. Since most mutations result in failure of the organism to thrive (death, reproductive failure, etc.) they have little or no effect on a population's gene frequencies. Even if the mutation has no apparent detrimental effects it will, itself remain in the population at a low frequency unless it enhances the organism's ability to reproduce within the population.
What does the q represent in hardy-weinberg equation?
It depends on what you make p equal to. P is usually the frequency of the dominant allele, which makes q the frequency of the recessive allele, but they can be switched. As long as p is one frequency and q is the other, the formula will work. So if you have the dominant allele frequency (A) =.6 then the recessive allele frequency (a) =.4, because p+q=1 When you plug the frequencies into the hardy-weinberg equation p^2 +2(p)(q) + (q)^2 = 1 then you have (0.6)^2 + 2(0.4)(0.6) + (0.4)^2 = 1 (0.6)^2 = 0.36 which is the frequency of dominant homozygotes 2(0.4)(0.6)=0.48 which is the frequency of heterozygotes (0.)^2 = 0.16 which is the frequency of recessive homozygotes If you have a population of 100 people, these frequencies would mean that: 36 people would be AA 48 people would be Aa 16 people would be aa Which would mean that 36+48=84 people would exhibit the dominant trait and 16 people would show the recessive trait.
In a certain population the dominant phenotype of a certain trait occurs 91 of the time what is the frequency of the dominant allele?
p^2+2pq=.91-->q^2=.09-->q=.3-->p=.7-->p^2=.49 p^2+2pq+q^2=1.49+2pq+.09=12pq=.42 the number of AA alleles =140-->49*2 + 42*1=140the number of AA alleles=60-->42*1 + 9*2=60 So the frequency of the dominant allele is equal to the number of dominant alleles over the total number of alleles.Therefore 140/200=.7.7 is frequency of the dominant allele
The Hardy-Weinberg principle is written as the equation p2 plus 2pq plus q2 1. What does p represent?
p represents the square root of the frequency of the homozygous genotype AA.
What is the answer for the Hardy Weinberg equation?
p2 + 2pq + q2 = 1 and p + q = 1p = frequency of the dominant allele in the populationq = frequency of the recessive allele in the populationp2 = percentage of homozygous dominant individualsq2 = percentage of homozygous recessive individuals2pq = percentage of heterozygous individuals
How calculate the frequency of alleles in population?
If you have the alleles A and a, then the The hardy-weinberg equation is: A2 + 2Aa + a2 = 1 where a and A represent allele frequencies. So A2 would be the genotype frequency for AA. 2Aa is the genotype frequency for Aa. And a2 is the genotype frequency for aa. Plug in whatever information you have into the equation and you can probably come up with an answer. Save
