You can use the formula: E = hc / lambda
Where: "h" is Planck's constant; "c" is the speed of light; "lambda" is the wavelength.
Visible light and radio waves are both two types of the same radiation (electromagnetic waves). The difference is that visible light has a higher frequency; a higher energy per photon; and a smaller wavelength.
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
Nope. Radio waves have a long wavelength, which causes them to carry little energy. For future questions about energy and waves, use the formula E=h(c/lambda). E is the energy of the wave, h is plank's constant, c is the speed of light (3x10^8), and lambda is the frequency. Have fun! ^_^
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
If the wavelength is longer, then the frequency is lower and the energy is less.
680 KHz: λ (wavelength) = about 0.2739 miles and photon energy is 2.8122488E-09 electron volts.
372.48 nano joule
Wavelength = (speed) divided by (frequency) =300,000,000 meters per second / 820,000 = 365.6 meters (rounded)-- 1,199.5 feet (rounded)-- 0.227 mile (rounded)
(300,000,000 meters per second) / (750,000 waves per second) = 400 meters per wave
There is no such thing as "long energy" or "short energy". The electromagnetic spectrum is:Radio waves; microwaves; infrared; visible light; ultraviolet; x-rays; gamma rays. In this list, going from left to right: * The energy per photon increases. * The frequency increases. * The wavelength decreases. Thus, for instance, gamma rays have the LARGEST energy per photon; the LARGEST frequency; and the SHORTEST wavelength.
the lowest frequency Lester was here
Visible light and radio waves are both two types of the same radiation (electromagnetic waves). The difference is that visible light has a higher frequency; a higher energy per photon; and a smaller wavelength.
Their wavelength (or frequency), the energy carried by each photon, and the names we give them. Their speeds are all the same.
The relationship between electromagnetic energy (photon energy) and wavelength is determined by two constants - the speed of light and Planck's constant. Photon energy (in Joules) is equal to the speed of light (in metres per second) multiplied by Plancks constant (in Joule-seconds) divided by the wavelength (in metres). E = hc/wavelength where: E is photon energy h is Planck's constant = 6.626 x 10-34 Js c is the speed of light = 2.998 x 108 m/s This relationship shows that short wavelengths (e.g. X-rays) have high photon energies while long wavelengths (e.g. Radio waves) have low photon energies.
Their wavelength (or frequency), the energy carried by each photon, and the names we give them. Their speeds are all the same.
Their wavelength (or frequency), the energy carried by each photon, and the names we give them. Their speeds are all the same.
Nope. Radio waves have a long wavelength, which causes them to carry little energy. For future questions about energy and waves, use the formula E=h(c/lambda). E is the energy of the wave, h is plank's constant, c is the speed of light (3x10^8), and lambda is the frequency. Have fun! ^_^