Want this question answered?
Several things affect blood osmolarity such as solute concentration, # of RBC's, albumin, salt, NaCl.
No,5percent glucose is an isotonic solution. 0.9 percent is for NaCl.
If you have a semipermeable sac containing 4 percent NaCl, 9 percent glucose, and 10 percent albumin is suspended in a solution with the following com- position: 10 percent NaCl, 10 percent glucose, and 40 percent albumin. The glucose will move into a semi-permeable sac.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
A student placed 15.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 40.0mL sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100. mL of the final solution?
Osmolarity is defined as the # of particles in solution.A rule to keep in mind is likes dissolve likes. So a covalently bonded substance like oil will only dissolve in a covalent solution. Same for polar substances etc.That said, glucose being covalent, will NOT dissolve in water, while the ionic compound NaCl will.The result is:Glucose --> GlucoseNaCl --> Na+ and Cl- (Both are ions)By the definition of osmolarity, glucose only produces 1 mol of particles, while NaCl produces 2. Those two numbers are their respective osmolarities.
calculate the osmolarity of a solution ; 1m of sucrose at 25 degree centigra 2m kcl at 25degree centigre 154mM Nacl at 25 degree
315?
Because NaCl produces double no of particles(Na+ and Cl-) in solution as compare to Glucose (C6H12O6)
yes
The osmolarity is 4 osmol/L.
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
No. Everything below 0.9% of NaCl is hypotonic and every solution with concentration over 0.9% is hypertonic solution. Isotonic solution (to blood) is the one that has 0.9% of NaCl, or some other concentration of another compound.
suspended in a solution with the following composition: 10% NaCl, 10% glucose and 40% albumin.
Several things affect blood osmolarity such as solute concentration, # of RBC's, albumin, salt, NaCl.
A solution is only isotonic compared to another solution. The statement that .9 NaCl is isotonic is incomplete. You are referring to the fact that it is isotonic with blood serum. This means they have the same osmotic pressure as each other which controls how they pass through the semi permeable membrane of blood vessels. .9 NaCl is isotonic with blood serum and that means that it will diffuse out of the blood vessel after IV injection in a similar fashion to the components of the blood serum itself. .9Nacl contains about 154 mOsm/L of Na and 154 mOsm/L of Cl giving the solution an osmolarity of 308 mOsm/L. The osmolarity of blood is about 300-310 mOsm/L so the two are very close and that's why .9NaCl is considered isotonic for IV solution.
No,5percent glucose is an isotonic solution. 0.9 percent is for NaCl.