The ohms will usually stay the same unless the Amps are somehow effecting the temperature. The Amps will always change with the volts.
To calculate volts, you also need to know the resistance (ohms) in the circuit according to Ohm's Law. The formula to find volts is V = I x R, where V is voltage, I is current in amps, and R is resistance in ohms. So, to determine volts given 0.01 amps, you'd need the resistance value.
Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms. To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance. 1 Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit. 2 Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit. 3 Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms. 4 To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance
6 amps.
The equation, I=V/R (Current = Voltage/Resistance) determines the current, so if you increase both V and R, you will be able to get the same current (with a bit of adjustment to make it exact)example:10 Volts & 2 Ohms resistance = 5 Amps Current20 Volts & 4 Ohms resistance = 5 Amps Current
Ohms law is E=IxR. Kirkoffs law has to do with the distribution of voltage and amperes. The amperes in a series circuit is always the same and the voltage changes. In a parallel circuit the voltage is always the same but the amperes change. You can find all the values in a circuit with limited information using these two laws.
Not necessarily. In a simple circuit V=IR, so if the resistance in a circuit remains constant, then voltage and current are directly proportional, so an increase in one will increase the other. If you were to change resistance and keep voltage constant, then the current would be inversely proportional to resistance, so as resistance went up, current would go down.
No.
You describe a series circuit. This answer is for a series circuit. The total impedance is 16 Ohms, 12 + 4. The current by Ohm's Law (Amps = Volts / Ohms) is 40 / 16, or 2.5 Amps. Kirchoff's Current Law says that the current at every point in a series circuit is the same, so the current flowing into the 1st device, the 12 Ohm resistor, is 2.5 Amps.
Could be zero, could be 1000 amps. Amps are not the same thing as volts.
Specifically, Volts and Amps would be called VA or volt amps, as in the rating of a transformer, but it is loosely referred to as Watts. In DC theory, Volts mulitplied by Amps equals Watts. In AC theory, that same equation exists but it includes power factor. If the power factor given is 1 (100%), then Volts mulitplied by Amps multiplied by Power Factor of 1 equals your Watts.
Yes, the amps stay the same but the voltage doubles. If you connect in parallel the volts stay the same and the amps double.
V=I*R Where: V is voltage I is the current in ampers R is resistance in ohms. So, if the current is 15 A and the resistance is 5 ohms, then the voltage must be 15 A *5 ohms = 75 V.