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The number in front of the different formulae within a chemical equation tells you how many molecules of that type are needed to react with the other molecules, as well as how many molecules of each product are produced. For example, when ethanol (alcohol) undergoes combustion with oxygen to produce water and carbon dioxide... CH3CH2OH + 3O2 --> 3H2O + 2CO2 ...for every molecule of ethanol, you need 3 molecules of oxygen for it to react with, and 3 molecules of water and 2 molecules of carbon dioxide will be produced. Of course, reactions don't generally involve just a few molecules. Really, these number give you a ratio of reactants and products. In a real situation, 1000 molucules of ethanol might react with 3000 oxygen molecules to produce 3000 water molecules and 2000 molecules of carbon dioxide (because 1:3:3:2 = 1000:3000:3000:2000 = 2:6:6:4 etc.) To work out what these numbers are can be a little tricky, but you basically have to make sure that the number of each element is the same on both sides of the equation (in the equation above, you can count 2 x carbons, 6 x hydrogens and 7 x oxygens on each side of the arrow). Hope this helps!
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
Balanced: 2CO+O2 --> 2CO2
2 CO2 means there are two molecules of carbon dioxide. In one molecule of CO2 there is 1 carbon atom, and 2 oxygen atoms. So three atoms total. Therefore, in 2 molecules (each with 3 atoms) there are 6 atoms total. The molecules are made of atoms of carbon and oxygen. The atoms themselves are made of protons, electrons, and neutrons.
Four oxygen atoms
two carbon atoms and two oxygen atoms present
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nnkn
One molecule of CO2 has one carbon atom and two oxygen toms. denoted by the formula CO2 So in two molecules of CO2 there are CO2 & another CO2 . Chemically this is shown as 2CO2, that is a figure is placed to the left of the molecular formula. Since there are CO2 & another CO2 , then there are two(2) atoms of carbon and four(4) atoms of oxygen.
You multiply the coefficient times the subscripts (number of atoms of each type in the formula) to get the total number of atoms of each element. For example: 2CO2 means 2 carbon atoms and 4 oxygen atoms (No subscript is understood to be 1.) 3C6H12O6 means 18 carbon atoms, 36 hydrogen atoms, 18 oxygen atoms
how do you draw it.
When yeast respires anaerobically it takes glucose (C6H12O6) and breaks it into ethanol, a small amount of energy, and two molecules of carbon dioxide gas (2CO2).
2khco3 + h2so4 ---> k2so4 + 2co2 + 2h20
(nh4)2co2
Here we're going to assume none of the acetylene gets a chance to escape into the atmosphere. Since it's lighter than air, we'll have to...I don't know, react it in a jar or something. We know the reaction we're going for is: C2H2 + n(O2) (meaning we have more oxygen than we could ever use) -> 2CO2 + H2O + n(O2) Therefore, to get the number of molecules of CO2 from this reaction, just double the molecules of acetylene and you're golden. How acetylene ACTUALLY burns is a little different. Three reactions occur simultaneously: C2H2 + O2 -> 2CO + H2 2CO + O -> 2CO2 2H2 + O2 -> 2H2O It does this because acetylene is so energetic it can't wait to split two molecules of oxygen apart before it reacts. But at the end of it, you still get two CO2 molecules for every acetylene molecule.