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The mass of sulfuric acid is 490,395 grams.

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Q: If you need 5 moles of sulphuric acid how many grams of it will you weigh?
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How do you prepare 2.5 M sulphuric acid?

1. Add 80mls of distilled water in a beaker. 2. Now add 20mls of concentrated sulphuric acid in small quantities while stirring with a glass rod.


How much does a ml of 36N sulfuric acid weigh?

a ml of 36n or 18m sulphuric acid should weigh approx 1.84g. This is because conc sulphuric acid's density is 1.84g/ml


Why is the enthalpy of reaction between sodium hydroxide and sulfuric acid different from that of sodium hydroxide and hydrochloric acid?

sulphuric acid is a diprotic acid so has two H+ and needs two moles of sulphuric acid to neutralise it


What equation is sulphuric acid mixed with copper oxide?

Cu + 2H2SO4 -> CuSO4 + 2H2O + SO2 Copper (Cu) on reacting with two moles of sulphuric acid (H2SO4) yields copper sulphate (CuSO4) and 2 moles of water (2H2O) and sulphur dioxide (SO2).


What is the mass of sulphuric acid?

The molar mass of sulfuric acid is 98 grams per mole.


2.943g of pure sulphuric acid H2S4 is dissolved in water to make 150.0 cm3 of solution What is the concentration of the solution?

The concentration of a solution is moles/volume. 2.943g of pure sulphuric acid H2S4 is approximately 15 moles, and 15/150 cm3 is 10.


How many grams h2so3 are found in 0.001874 moles?

0.1538 grams


How many grams would be in four 4 moles of nitric acid HNO3?

4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================


How many moles of formic acid is there in 25 grams of acetic acid?

I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================


What percentage concentration is 60 grams per liter sulphuric acid?

3.33%


How many grams are in 2.5 moles of sulfuric acid?

The mol mass of sulfuric acid is 98.078 g/mol, 98 g of sulfuric acid therefore contains 0.9992 moles. Using consistent significant figures and your calculations, 98 g sulfuric acid would be equal to 1.0 mol sulfuric acid.


How many moles of excess sulfuric acid are left over after the complete reaction of 300.0 g of ammonia with 36.0 moles of sulfuric acid producing ammonium sulfate?

The equation for the reaction is: H{2}SO{4} + 2NH{3} → (NH{4}){2}SO{4} [Numbers in braces are supposed to be subscripts, but I can't do them here.] This says that 1 mole of sulphuric acid reacts with 2 moles of nitrogen to create 1 mole of ammonium sulphate. 1 mole of a substance weighs the same as its atomic weight in grams. 1 mole of NH{3} weighs 14 + 3 × 1 = 17 g Thus 2 × 17 g = 34 g of ammonia react with 1 mole of sulphuric acid. To react with 300 g of ammonia requires 300 g ÷ 34 g/mol ≈ 8.8 moles of sulphuric acid Therefore there will be 36.0 - 8.8 = 27.2 moles of sulphuric acid left.