The net force equals mass times acceleration. So if mass is held constant then the acceleration should also triple.
the magnitude of the force will be increased by a factor of 4
F1=m*a0
3F1=m*a
F1=(m*a)/3
m*a0=(m*a)/3
a=3a0
As you can see, if the net force was tripled, the car's acceleration would also triple.
When you double the distance between 2 charges it reduces the original value by 1/4th
The forces in each direction are quadrupled.
1/9 of what it was before they were moved.
increase 3 times
The force between the two charges increases 16 times.Coulomb's law equation states:│F│ = ke │q1q2│/r2Where (F) is the force acting simultaneously on both point charges (q1) and (q2).r is the separation distance and ke is a proportionality constant called the Coulombconstant.Using above equation, if we double both charges and reduce the distance in half.│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.We see that the force turns out 16 times stronger
The force is proportional to each of the masses. For example, if one of the masses is doubled, the gravitational force will also double.
1,000 newtons, provided the distance between them didn't change.
The electric force will be quarter of its strength.
The moon might escape it's orbit and become a moon of another planet.
If the magnitude of each of two charges is doubled, then the direction of the force between them doesn't change, but its magnitude increases by a factor of 4.
The force is proportional to the product of the two charges.If each charge is doubled, the force increases by a factor of 2 x 2 = 4 .
I dont know haha you tell me.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Force of attraction between charges is directly proportional to the charge. So as we quadrule each charge then force will become 4x4 ie 16 times increased Force is also inversely related to the square of the distance. So as we double the distance then the force is decreased by 22 ie 4 times Hence the net change will be 16/4 ie 4 times increase in the force of attraction.
Doubled
Whatever be the magnitude of charge, two charges will always exert equal force on each other. As force depends on the product of magnitude of charges, it will increase if magnitude is doubled but will remain same for both the charges.
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
We have to assume that the distance between the charges remains constant, and the answer doesn't depend on the distance. The force between the charges is proportional to the product of the charges. Initial force = constant x (Q1) x (Q2) New force = constant x (2Q1) x (3Q2) = 6 x (Q1) x (Q2) = 6 times the initial force. The direction of the force doesn't change. It's attractive if the charges are of opposite sign, repulsive if they're of like sign.
The force between charges decreases as the distance between them increases. Like charges repel each other. Oppostite charges attract each other
That's the force of repulsion between two positive charges; or between two negative charges.
Yes if the quantities of the charges are unchanged.