implement it. enough said.
used as mux and demux , used for implement haff adder $ full adder, by program it
yes, given MUX in number To be implemented MUX 2:1MUX x 3 4:1MUX 4:1MUX x (4+1) 16:1MUX 4:1MUX x (16+4+1) 64:1MUX 8:1MUX x (8+1) 64:1MUX 8:1MUX x (32+4+1) 256:1MUX
we'll get 4 input mux cuz 2^4=16.... therefore the first 4 input mux has 16 o/p.. hence four-4 i/p mux are required to fill all 16 leads.
If you want to have output z = A NOR B. Make select line of 2X1 MUX = A. Now, the first i/p line (corresponding to A =0) = B ' BAR tthe second i/p line (corresponding to A=1) = 0.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
used as mux and demux , used for implement haff adder $ full adder, by program it
what is a mux
using 8:1 mux....
A CMOS Mux is a piece of technology that is used to create integrated circuits that are used in electronics. The full name of 'CMOS' is Complementary Metal Oxide Semiconductor.
Advantages are 1: it reduces number of wires. 2:it reduces circuit complexity and cost. 3:it simplifies logic design. 4:we can implement many combinational circuits using MUX. 5:it does not need kmaps and simplification.
yes, given MUX in number To be implemented MUX 2:1MUX x 3 4:1MUX 4:1MUX x (4+1) 16:1MUX 4:1MUX x (16+4+1) 64:1MUX 8:1MUX x (8+1) 64:1MUX 8:1MUX x (32+4+1) 256:1MUX
To design an OR using 2:1 mux, we need to tie the "First" input to "Logic 1″ and the "Zeroth" input to the one of the input of the OR Gate. The other input of OR gate would be connected with the select line of the MUX. Now, the output of the MUX would be "1″ when any oth the two inputs would be "1″ otherwise it would be "0″ for all conditions.
we'll get 4 input mux cuz 2^4=16.... therefore the first 4 input mux has 16 o/p.. hence four-4 i/p mux are required to fill all 16 leads.
As of July 2014, the market cap for McEwen Mining Inc. (MUX) is $706,322,326.55.
If you want to have output z = A NOR B. Make select line of 2X1 MUX = A. Now, the first i/p line (corresponding to A =0) = B ' BAR tthe second i/p line (corresponding to A=1) = 0.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
a mux has many i/ps & 1 o/p but a router connects many n/ws and the may or may not be of same kind a mux does not follow an algo but router follows algo such as dikakstra bellman ford or any other or a combination.......