Both parents are Dd. They express the dominant gene but carry the recessive one, so there's a 25% chance that the pup will express the recessive one. If either parent was DD, then it would be impossible to produce a pup that expresses the recessive gene.
They will produce gametes that are also homozygous.
If the parent generation consisted of a homozygous dominant parent and a homozygous recessive parent, then the F1 generation would be 100% heterozygous.
dominant parent traits.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
dominant parent traits.
Co-dominance happens when two genotypes are expressed at the same time. For example, one parent can have blood type A and one parent can have blood type B and together produce a child with blood type AB. If two parents have the blood type AB, the child has a chance of being mentally ill.
Rr
The offspring in the first column both have two dominant T alleles. Therefore, you know that the father (parent on the left hand side) is TT and the mother (parent on the top) has a dominant T in that column too. The offspring in the second column are Tt. The dominant T came from the father, as figured out in the first part of the problem. The recessive allele t came from mother's second empty box.
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
I it AA in both parent
If the phenotype is recessive then the genotype must be dd.
both must be tt or both must be Tt