If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator.
12 Volt and One 12 Watt lightbulb drains 1 Ampere Current.
12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current.
However:
If having a 24 volt powersource and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current.
NOTE:
Wattage and Voltage of bulbs may be different even if the sockets are the same.
Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second.
It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for.
Total Current/Ampere= Combined Wattage divided by Voltage
Total Wattage = Combined Current or Ampere multiplied by Voltage.
Regards.
It is halved. coz voltage=current * resistance
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
If resistance is halved while voltage remains constant, the current will double.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
Voltage attempts to make a current flow, and current will flow if the circuit is complete. It is possible to have voltage without current, but current cannot flow without voltage. The answer is "yes",voltage remains the same as current moves through the circuit.As the voltage remains constant, current increases in the circuit.
It is halved. coz voltage=current * resistance
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
I = E/R If resistance is constant, then current is directly proportional to voltage. Double the voltage ===> the current will also double.
V = IR Where, V = voltage I = current R = resistance Thus if resistance is increased with constant voltage current will decrease
Inversely. As resistance increases, current dereases; given that the applied voltage is constant.
That depends on the components in the circuit: resistive, reactive, nonlinear, etc.
If resistance is halved while voltage remains constant, the current will double.
Current will increase
If the ratio of voltage to current is constant, then the circuit is obeying Ohm's Law. If the ratio changes for variations in voltage, then the circuit does not obey Ohm's Law.
it will cause a Short Circuit
No it cant. Voltage = Current x Resistance. So at constant Voltage if the Resistance is increased, Current will reduce