The answer below should be that they will all be black: the last portion is right (3 homo. black to 1 het. black) but all the mice will have black coats.
3 black to 1 white, ......B equals black, w equals white, 3homozygous black to 1 heterozygous black.
There only certain crosses that will produce heterozygous offspring. These are heterozygous vs heterozygous, homozygous vs homozygous and heterozygous vs homozygous.
genotype means genetic make up. it can give the information about the parents wether they were homozygous or heterzygousAnswer (Improved)A genotypic ratio is the proportion of genotypes found in individuals after a cross. For example, consider a cross between two heterozygous individuals for trait A: Aa X AaThe result is a 1:2:1 ratio for the genotypes AA, Aa, and AA respectively. Put another way, if the parents had 100 offspring, 25 would be expected to have the genotype AA, 50 the genotype Aa and 25 the genotype AA.This is hard Good Luck
You could try breeding it with a homozygous recessive partner (hh) Lets assume that you breed the original mystery rabbit with an hh recessive partner, and they have 10 offspring. If the original rabbit is homozygous dominant, it would be HH + hh, which would give all 10 the offspring Hh genotypes, which would give them the dominant hair color. If it was heterozygous dominant, it would be Hh + hh, which would lead to either Hh or hh offspring. This means that in theory, 5 would be dominant colored while the other 5 would not be.
In genetics, you can either have a dominant allele (A) or a recessive allele (a). Being homozygous means that you have both of either a dominant or a recessive allele (ie you are either AA or aa). If the trait is a recessive trait, then you need to have it be homozygous recessive in order to express that trait. Hope this was helpful! :-)
if heterozygous, yes
Assuming there is no co-dominance or partial dominance, the result would be that 100% of the offspring would be blue, heterozygous flowers with the phenotype Bb.
There only certain crosses that will produce heterozygous offspring. These are heterozygous vs heterozygous, homozygous vs homozygous and heterozygous vs homozygous.
of two different phenotypes
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
The genotype each offspring has is determined by the parents. They can be both homozygous dominant or are they heterozygous and homozygous(dominant or recessive)
Two types: A heterozygous parent (Aa) and a homoygous recessive parent (aa) can produce phenotypically dominate and phenotpically recessive offspring (with 50% genotypes Aa and the other 50% aa). If the genes are co-dominate then the offspring can have blended traits and recessive traits phenotypically.
A trait that exhibits incomplete dominance, is one in which the heterozygous offspring will have a phenotype that is a blend between the two parent organisms. An example of this is when a homozygous red sweet pea flower crossed with a homozygous white sweet pea flower, their offspring will be heterozygous and have the pink phenotype, rather than either red or white. So, the homozygous red flower will be red, the homozygous white flower will be white, and the heterozygous flower will be pink. So there are three possible phenotypes in incomplete dominance. There are also no dominant or recessives genotypes.
The phenotypes of attached and unattached earlobes do not fit neatly into the Mendelian theory of two alleles for one trait, and there is a continuum of earlobe phenotypes. That said, unattached earlobes are a dominant trait, so if the individual is homozygous for unattached earlobes, all of her offspring will have the unattached phenotype, even if some or all of them are heterozygous.
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
Using Punnett Squares, you can predict the genotypes and phenotypes of the offspring of a cross between a homozygous (purebred) tall pea plant and a homozygous (purebred) short pea plant.