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There are 120 ways to order a 5 letter word, however, since there are two "e" letters in the word "green", the number of combinations is only 60.
You can arrange the letters in "the letters in the word Hornet", in 7,480,328,917,501,440,000 different ways. There are 25 letter in all, but there are 2 each of n and o, 3 each of h and r, 5 each of e and t. So the number of ways is 25!/[2!*2!*3!*3!*5!*5!] where n! = 1*2*3*...*n
5!/2=60 [If all the letters were different, it would be 5!=120. But you need to divide by two since "e" appears twice.]
Depends on the t's and e's are different or not. There are 10 letters and 10 'spaces' for them to be in. The first space has 10 different candidates. The second has 9. The 3rd has 8 and so on. So there are 10! = 3,628,800 different ways to arrange the letters. That is if the t's and e's are different. . If literaturE is the same as litErature, then we have all possibilities twice concerning the e's. 3,628,800 / 2 = 1,814,400 . The same goes for the t's. 1,814,400 / 2 = 907,200 . Ergo: 907,200 or 3,628,800 ways.
First, count how many letters you have--A, B, C, D, E, and F--6. Then, the problem is the number multiplied by the ones below it. 6x5x4x3x2x1. You can get rid of the one, because anything multiplied by 1 is itself. 6x5x4x3x2=720. You can arrange these six letters in 720 possible ways. If the row could be vertical or horizontal, the number doubles to 1440.
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If the order matters, i don't know, but if matter doesn't matter you can arrange the letters to get 120 orders.
r b l j a y c e a
There are 6! = 6*5*4*3*2*1 = 720 ways.In half of these b will be to the left of e and in the other half it will be to the right. So the answer is 360 ways.
You arrange the bones so that the bones form the letters "T-E-N" (2 bones, 4 bones, 3 bones).
If one of the three Is was meant to be an L, those letters can be used to spell "live with me".