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Q: In humans the allele for brown eyes (B) is dominant to the allele for blue eyes (b). What is the probability that two heterozygous brown-eyed parents will have a child with blue eyes?
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What is the probability that the children will be heterozygous?

Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.


What is probability that wto heterozygous parents would have an offspring that produced round seeds?

75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.


What is the probability that two heterozygous parents would have an offspring that produced round seeds?

The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.


If purple flower color is dominant over white flower color how can two purple flowered parents produce while flowered offspring?

It can happen when both parents are a heterozygous


What was the probability that two heterozygous parents would have an offspring that produced round seeds?

25%


Is it possible for blue eyed parents to have a brown eyed baby?

Yes, buy only if the parents are heterozygous for the trait and if the trait is dominant.


What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?

3:4 or 75%


What is probability that two heterozygous parents would have an offspring that produced round seeds?

It is a 75% chance that the seeds will be round.


What is an example of two heterozygous parents?

The possible genotypes of parents who are heterozygous would be found using a punnet square. The outcome would be 50 percent heterozygous dominant, 25 percent homozygous dominant, and 25 percent homozygous recessive.


What are the genotype a of the parents?

genotype of the parents - parents will be heterozygous dominant. e.g. take the example of Mendel's pea cross. if parent is heterozygous dominant then the genotype will be Tt and Tt now if you will do a cross then the result you will get is this - Tt X Tt result - TT, Tt, Tt, tt it gives a 3 : 1 ratio i.e. three tall and one dwarf. Source: "tumul v" yahoo.answers


In incomplete dominance genotypes can be expected to appear in a ratio of?

The expected phenotype for a Mendal F1 monohybrid cross is 3:1. Looking at heterozygous parents (F1) who share the same dominant trait, e.g. Straight tail.Crossing two heterozygous parents from the F1 generation results in an F2 generation that produces a 75% chance for the appearance of the dominant phenotype, of which two-thirds are heterozygous, and a 25% chance for the appearance of the recessive phenotype, giving the ratio 3;1.Inheritance pattern of dominant and recessive phenotypes when each parent is homozygous for either the dominant or recessive trait. All members of the F1generation are heterozygous and share the same dominant phenotype, while the F2generation exhibits a 3:1 ratio of dominant to recessive phenotypes.


If purple flower color is dominant over white flower color how can two purple flowered parents produce white flowering offspring?

It can happen when both parents are a heterozygous