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Actually, it is the recessive.................................................................UR WELCOME! :)
In order for a recessive trait to appear in the offspring, it must inherit a recessive allele for that trait from both parents.
Dominant traits only require one allele to be present in order for the trait to be expressed, while recessive traits must have both alleles present in order for the trait to be expressed.
An organism which shows a dominant trait can be classified as pure breed or hybrid by test crossing it. In test cross, the organism is crossed with a recessive one. If the F1 progeny shows a dominance-recessiveness ratio of 1:1, it means that the organism was a hybrid. If the f1 progeny shows a ratio of 3:1, it means that the organism was a pure breed.
This genetic condition is likely an autosomal recessive trait since it occurs with equal frequency in males and females. If neither parent is affected, it suggests that both parents are carriers of the condition. In order for a child to be affected, they would need to inherit two copies of the recessive allele, one from each carrier parent.
Actually, it is the recessive.................................................................UR WELCOME! :)
An individual must have 2 recessive alleles in order for a trait to show up. One must only have 1 dominant allele in order for a trait to occur.
Recessive traits require two recessive alleles.
In order for a recessive trait to appear in the offspring, it must inherit a recessive allele for that trait from both parents.
Dominant traits only require one allele to be present in order for the trait to be expressed, while recessive traits must have both alleles present in order for the trait to be expressed.
This most commonly occurs if the disorder is recessive, meaning you must carry two copies of the gene which causes the disorder in order to show it.Everyone has two copies of each gene, one paternal and one maternal. If you only carry one copy (allele) of the gene which causes the recessive disorder and your other copy of that gene is normal, you will not have the disorder. However, you can carry it on if you have a child with someone else who also carries the gene which causes the disorder and the child gets two copies of the disorder gene.
Neither of the parents will be affected. There may not be any one with he disease in either of the parents families (or there might be). Since each parent is a carrier and has a 50/50 chance of passing one copy of the gene to each child 1/4 of the children will not get the gene, 1/2 will be carriers (1 copy) and 1/4 wil be affected (2 copies).
In genetics, you can either have a dominant allele (A) or a recessive allele (a). Being homozygous means that you have both of either a dominant or a recessive allele (ie you are either AA or aa). If the trait is a recessive trait, then you need to have it be homozygous recessive in order to express that trait. Hope this was helpful! :-)
Males have XY - therefore they only need one copy of the defective X in order to have the disorder.Females have XX - meaning they would need two copies of the defective allele in order to have the disorder. This means their father must have the disorder, and their mother must either have the disorder or be a carrier.
Dominant alleles carry traits or characteristics that will show no matter what. Recessive alleles carry traits where you must be homozygous for the recessive trait in order for it to show. Dominant alleles are represented by capital letters (EX: R or M) Recessive alleles are represented by lower case letters (EX: r or m) In order for a dominant allele to show, you can have either RR or Rr, since it is dominant. However, in order for a recessive allele to show, you MUST have rr. Hope this helps!
it is because the parents each were heterozyous dominant. meaning each of them had a dominant allele and a recessive allele. the dominant allele would be the curly hair, and the recessive allele would be the straight hair. There would be a 1/4 chance that the child would have curly hair, and a 3/4 chance that they would have curly hair. Say that the Curly hair allele was H and the straight hair allele was h. In order for the parents to have curly hair, they would either have to have an HH gamete or an Hh gamete. Seeing as though the child came out with curley hair, both parents would have to have an Hh gamete. In order to find out the probability, you multiply the parents gametes. (Hh)(Hh). This will give you HH, Hh, Hh, hh. seeing has three of the gametes have the dominant allele, this child will have curly hair, and one is a homozygous recessive, so it will turn out with straight hair.
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.