the voltage across each is the same
NO
Yes more batteries/power equals more brightness to a source
V=IRyou are adding in parallel, so V is non-zero, because R is positive, I must have the same sign as V. Therefore your current will increase.
If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.
to boost current, you parallel in additional sources. Such as adding batteries in parallel.
no
it doesn't, in a parallel circult the volage stays the same therefore the brightness will stay the same
Just by adding
by adding resistance in parallel more current is bound to flow
Adding more lamps in parallel (across) a line will cause total current to climb. It will keep climbing (increasing) until a load protection device (circuit breaker or fuse) breaks the circuit or until something fails because of excessive current.
Var is controlled by adding inductors or capacitors in parallel with loads requiring reactive power. By adding a capacitor of proper size in parallel with a inductive load results in the load drawing VAR from the capacitor instead of the source.
The brightness of the lights may or may not change depending on the circuit in which they are wired. In a series circuit, all the bulbs (called lamps) will experience the same current flow. The same amount of current will be flowing through each one, and each one will be dropping some amount of voltage. If we remove some of the lamps and reconnect the circuit, the lamps will glow brighter because there is less total resistance in the circuit. The remaining lamps will end up dropping more voltage, and will glow brighter. In a parallel circuit, removing bulbs (or adding them) will not affect the operation of the other lamps in the circuit (providing the voltage source is adequate). We know that each of the lights in a household circuit is wired in parallel, and turning one or more on or off won't affect the operation (the brightness) of any other light that is on.