Q: 2C2H6 plus and ?O2 yields 4CO2 plus 6H2O
First balnce this equation for oxygen (?) (Carbon and Hydrogen are already correctly balanced): right sided O counting 4x2 + 6x1 = 14, so left sided there should be also 14 atoms O or 14/2 = 7 moleecules O2
2C2H6 + 7O2 --> 4CO2 + 6H2O
Then divide both sides by 7 and multiply by 5 (7*5/7 O2 and 4*5/7 CO2) to find -->
A: 5 mole O2 will yield (20/7=) 2.86 mole CO2
Five moles of O2 are needed to react with 2.00 moles C2H2. The symbol O2 stands for Oxygen, and C2H2 stands for acetylene.
I assume you mean this reaction.
2H2 + O2 -> 2H2O
2.0 moles H2 (1 mole O2/2 mole H2)
= 1.0 moles O2 needed
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Write and balance the equation:
C2H6O + 3 O2 --> 2 CO2 + 3 H2O
(3moles O2 / 1 mole C2H6O) x 4 mol C2H6O = 12 moles O2
7.2 mol of oxygen gas.
1.00 mole
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
7.54 mol of K
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
How many moles of C are needed to react with 0.490 mole SO2?
Balanced equation: 2H2S + 302 = 2SO2 + 2H20
Ca + 2 H2O ------> Ca(OH)2 + H2 so 2 moles of calcium react with 4 moles of water.
7.54 mol of K
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
Since molecules of potassium contain only single potassium atoms, molecules of iodine contain two atoms, and moles of potassium iodide contain one atom of each element, 2.5 moles of iodine are needed to react completely with 5 moles of potassium.
How many moles of C are needed to react with 0.490 mole SO2?
4 moles
The answer is 50 moles SiO2.
4 C3H8 + 20 O2 ---> 12 CO2 + 16 H2O So 20 mol of O2 are needed.
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
1 mole sulfuric acid for 1 mole calcium chloride
0.8 moles Explanation: from the equation we can see, 2 mole A l is needed to react completely with 3 mole F e O so, 3 moles of F e O needs 2 moles A l so, 1 mole F e O needs 2 3 moles A l so, 1.2 mol F e O needs 2 × 1.2 3 moles A l = 0.8 moles A l