MgCl2 would be the limiting reagent
MgCl2
MgCl2 + 2KOH ==> Mg(OH)2 + 2KClLooking at this balanced equation, one sees that every ONE mole of MgCl2 reacts with TWO moles of KOH. Thus, the mole ratio is 1 : 2. Therefore 1 mole MgCl2 is added to 3 moles KOH, there will be plenty of KOH since only 2 moles would be needed. Thus MgCl2 would be limiting.
Write the BALANCED reaction eq'n
2KOH + MgCl2 = 2KCl + Mg(OH)2
So in the molar ratios 2 moles KOH reacts with 1 mole MgCl2
Since we have 6 moles of each
Then 6 moles (KOH) only requires 3 moles MgCl2 ( but we have 6 moles)
So KOH is the limiting reactant leaving 3 moles MgCl2 unreacted,
The limiting reagent is potassium hydroxide.
KOH
MgCl2
Potassium hydroxide is the limiting agent.
The amount of Koh
2
MgOH2 is a base. It is also known as magnesium hydroxide and is commonly used as an antacid to neutralize stomach acid.
Inorganic (no carbons)
The answer is one mole.
Potassium hydroxide is the limiting agent.
The amount of Koh
2NaCl + Mg(OH)2 --> MgCl2 + 2NaOH Make sure to put the parentheses around the hydroxide. There is a difference between Mg(OH)2 and MgOH2.
2
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.
MgOH2 is a base. It is also known as magnesium hydroxide and is commonly used as an antacid to neutralize stomach acid.
Mg + 2HCl → MgCl₂+ H₂ When a metal reacts with an acid a salt and hydrogen are produced.
Inorganic (no carbons)
Magnesium hydroxide
The compound Mg(OH)2 contains 16% oxygen. This can be calculated by dividing the molar mass of oxygen by the molar mass of Mg(OH)2 and multiplying by 100.
Mg(OH)2 is a base. It is an alkaline earth metal hydroxide that dissociates in water to form hydroxide ions, which can accept protons from acids to neutralize them.