The chemical equation is:
2 K+ + (CrO4)2-(aq) + 2 Ag+ + 2 [NO3]-(aq) --> Ag2CrO4(s) + 2 K+ + 2 [NO3]-(aq)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
how many moles are there in 56.0 grams of silver nitrate?
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
2Ag(aq)+ CrO4(s)---->AgCrO4(s)
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
how many moles are there in 56.0 grams of silver nitrate?
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
Potassium nitrate is too stable and so is silver for these two species to react. There is thus no balanced equation.
Silver chromate is not soluble in water.
This equation is: 2 AgNO3 + K2CrO4 => Ag2CrO4 + 2 KNO3.
Silver chloride is 1/10 soluble than silver chromate in the cold 1/3 in hot water. That means silver will incline to precepetate as AgCl preferentially. More over if chromate will form it will convert to silver nitrate.
no
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3