No. First Na is not a diatomic element so Na2 is not correct. Oxygen is a diatomic element so if it is by itself, there has to be a sibscript of 2. A balanced equation would be 2 Na plus O2---- 2(NaO) plus you cannot have a number in the middle of the product.
The balanced equation for sodium reacting with water to yield sodium hydroxide and hydrogen gas is: 2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g)
NH4NO3 (aq) N2O (g) + 2H2O (l)
2F2 + 4NaOH >> 4NaF + O2 + 2H2O
H2+SO4-2 + 2Na+OH- >>> Na2SO4 + 2 H2O
Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
The balanced equation for the reaction of sodium with water is: 2Na (s) + 2H2O (l) -> 2NaOH (aq) + H2 (g)
2Na+2H2O------>2NaOH+H2
The balanced equation for sodium reacting with water is: 2Na + 2H2O → 2NaOH + H2
Simplified. 2NaOH + H2SO4 -> Na2SO4 + 2H2O
HCl + NaOH = H2O + NaCl is already balanced.
It has been a long time, but I think it has to read: 2Na + 2H2O --> 2NaOH + H2 to be balanced.
Sodium hydroxide does not react with hydrogen gas.
H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O H2SO4 + 2NaOH ------------> Na2SO4 + 2H2O
The balanced equation for sodium reacting with water to yield sodium hydroxide and hydrogen gas is: 2Na(s) + 2H2O(l) -> 2NaOH(aq) + H2(g)
The balanced chemical equation for the reaction of sodium with water is: 2Na + 2H2O -> 2NaOH + H2
The balanced chemical equation for the reaction between fumaric acid and aqueous sodium hydroxide is: C4H4O4 + 2NaOH → Na2C4H2O4 + 2H2O
2Na + 2H2O -> 2NaOH + H2