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Q: Is 43.98 g of sodium combines with an excess of chlorine gas to form 116.89 g of sodium chloride what mass of chlorine gas is used in this reaction?
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Why excess barium chloride is added to the filtrate in the preparation of a dry sample of barium sulphate?

Barium chloride in excess is added to be sure that the reaction is complete.


What mass of CCl4 is formed by the reaction of 8.00 g of methane with an excess of chloride?

76.7g


When 10.0 grams of calcium reacts with 20.0 grams of chlorine gas, how many grams of calcium chloride can be produced Which reactant is in excess and which is the limiting reactant?

The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.


In the reaction of silver nitrate with sodium chloride how many grams of silver chloride will be produced from 100 g of silver nitrate when it is mixed with an excess of sodium chloride?

58.9g


How many grams of zinc chloride can be formed from the reaction of 7.96 g of zinc with excess HCl?

The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.


When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?

4 moles


You are given 34.0 g of aluminum and 39.0 g of chlorine gas. If you had excess chlorine how many moles of aluminum chloride could be produced from 34.0 g of aluminum?

1.26 mol of AlCl3


What would be observed when a fresh precipitate of silver chloride is treated with excess ammonia solution?

When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.


Why is aluminum chloride used in large excess in Friedel-Crafts reactions?

To ensure there's enough of it to allow the reaction to go to completion.


When heated, sodium metal combines with chlorine gas to form solid sodium chloride. If 4.50g of sodium and 15.2g of chlorine are heated together, a total of 10.5 g of sodium chloride is isolated. Determine the percent yield of sodium chloride?

First write down the balanced reaction equation 2Na(s) + Cl2*g) = 2NaCl(s) The molar ratios are 2:1::2 Next calculate the moles of each substance mol(Na) = 4.50/23 = 0.1956 moles mol(Cl2) = 15.2 / (2x 35.5) = 0.2140 moles mol(NaCl) = 10.5/(23 + 35.5) = 0.1795 We now compare 2:1::2 ::: 0.1956/2 : 0.2140/1 :: 0.1795/2 = 0.0975 : 0.2140 ::0.0897 It will be seen that the chlorine is in excess. !!! So percentage yield of NaCl i s 0.0897x 100 / 0.0975 = 92.05%


Calculate the theoretical yield of calcium chloride expected for this reaction if 0.80 mol of calcium hydroxide is reacted with excess hydrochloric acid.?

0.80


What mass of sodium chloride is produced if 92.0 of sodium reacts with excess Chlorine?

Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).