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Barium chloride in excess is added to be sure that the reaction is complete.
76.7g
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
58.9g
The equation for the reaction is Zn + 2 HCl -> ZnCl2. The gram atomic masses of zinc and chlorine are 65.39 and 35.453 respectively. Therefore, the number of grams of zinc chloride that can be formed from 7.96 g of zinc is: 7.96{[65.39 + 2(35.453)]/65.39} or about 16.6 g of zinc chloride, to the justified number of significant digits.
4 moles
1.26 mol of AlCl3
When you treat silver chloride with excess ammonia solution, Diamine silver (I) chloride is formed . The reaction involved is- AgCl + NH(3) --->Ag( (NH(3)) 2)(+) + Cl(-).What you will observe is that AgCl is insoluble, but after adding ammonia it becomes soluble because of above reaction.
To ensure there's enough of it to allow the reaction to go to completion.
First write down the balanced reaction equation 2Na(s) + Cl2*g) = 2NaCl(s) The molar ratios are 2:1::2 Next calculate the moles of each substance mol(Na) = 4.50/23 = 0.1956 moles mol(Cl2) = 15.2 / (2x 35.5) = 0.2140 moles mol(NaCl) = 10.5/(23 + 35.5) = 0.1795 We now compare 2:1::2 ::: 0.1956/2 : 0.2140/1 :: 0.1795/2 = 0.0975 : 0.2140 ::0.0897 It will be seen that the chlorine is in excess. !!! So percentage yield of NaCl i s 0.0897x 100 / 0.0975 = 92.05%
0.80
Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).