Assuming that the intended reaction is BaCl2 (aq) + Na2SO4 (aq) => 2 NaCl (aq) + BaSO4 (s), this is not a redox reaction. Instead it is an ion interchange reaction, driven by the fact that BaSO4 is much less soluble in water than any of the other ions pairs barium chloride, sodium chloride, and sodium sulfate.
BaCl2 + K2SO4 --> BaSO4 + 2KCl
There are four basic types of chemical reactions. In this case, when sodium reacts with magnesium sulfate to form sodium sulfate plus magnesium, it is a single replacement reaction.
BaCl2 + K2So4 ----> BaSo4 + 2 KCl
It's a redox equation that's only if you meant to put 2FeCl3 and not CI3
Na2SO4+CaCl2 =====> CaSo4+2NaCl
This is a redox reaction.
Redox reaction.
first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck
NaNO3 + H2SO4
Probably as a Displacement reaction
Oxidation is a redox reaction.
No, it is not a redox reaction. None of the oxidation numbers changes during the reaction. You have to determine the oxidation number for each element and see if it changes from reactant side to product side. If the oxidation number doesn't change, it is not a redox reaction.
2NaCl + H2SO4 = Na2SO4 + 2HCl
I cannot answer this question.
yes
The balanced equation for sodium sulfate (Na2SO4) plus barium chloride (BaCl2) yielding barium sulfate (BaSO4) and sodium chloride (NaCl) is: Na2SO4 + BaCl2 -> BaSO4 + 2NaCl
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.