The chemical formula for iodomethane is CH3I.
Iodine is in: Iodomethane (CH3I) that is produced by the marine environment, by microbial activity in rice paddies and in Potassium iodide (KI) a very soluble salt.
The chemical formula for iodomethane is CH3I.
Formula: CH3I
non polar
Dipole-dipole and dispersion
CH3I + COONa + 3NaI + 3H20
No. This compound, butane, is covalently bonded.
This is a chemistry question not a math question. CH3I is methyl iodide, CH3COONa is sodium acetate, the chemical reaction produces the product CH3COOCH3 or methyl acetate. the other to chemicals are reactants. reactants react to produce products. Products are what you end up with. Reactants are what you start with.
Since there is 4 electron domains which are all single bonds without any lone pairs, the molecular geometry is tetrahedral.
Iodine is in: Iodomethane (CH3I) that is produced by the marine environment, by microbial activity in rice paddies and in Potassium iodide (KI) a very soluble salt.
Probably when you take a sugar with alcohol components (-OH), turn them into O- ions by using a basic conditions (say NaOH) and then alkalizing them to form esters (say CH3I). That would replace all alcohols with (-OCH3 esters). "esterification of sugars"
Well there is no acid, I repeat N O ! A C I D ! (cf. discussion page), with the formula HCI (with elements H, C, and I) because:HCI is a chemically impossible compound, or at least never been synthesizedIf it where then it wouldn't be an acid, rather a iodine-substituted hydrocarbon H(4-n)CI(n) with n = 1, 2 or 3 which all are not water soluble.The chemical name of this NONexisting compound CHI would have been mono-iodine methane (CH3I is possible) or tri-iodine methane (CHI3 is possible).
The CI bond is slightly polar due to the small electronegativty difference between C (EN 2.55)and I (EN 2.66). For example CH3I has a dipole moment of around1.62-1.64 D (different researchers have published different figures)