No, CuCO3, or copper carbonate is a compound made up of an element and a polyatomic ion.
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
Yes, that is correct. When copper carbonate (CuCO3) is heated, it decomposes into copper(II) oxide (CuO) and carbon dioxide (CO2).
on heating copper carbonate decomposes to cupric oxide which is black in colour.
Yes, NaCH3COO (sodium acetate) is soluble in water as are all sodium compounds.
This is not a decomposition reaction.
CuCO3 is copper carbonate.
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
Heating CuCO3 (copper (II) carbonate) produces carbon dioxide (CO2) and copper oxide (CuO).
There is one atom of carbon in this formula. The formula indicates one atom of Copper + one atom of Carbon + 3 atoms of oxygen. O3 added to any compound prompts the suffix -ate, so in this case, you have a formula for Copper Carbonate.
Molar mass of CuCO3 = 123.5549 g/mol Cu:26.4395 % Co:73.5605 %
The corresponding ionic reaction would be; Cu2+(aq) + CO32-(aq) -> CuCO3(s)
it is carbon and 2 oxygen atoms a.k.a carbon dioxide
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CuCO3
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CuCO3
copper carbonate