This solution would be close to nuetral but slightly basic, due to there being 2 Na+ moleucles and 1 SO4-2
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
The answer is 20,79 mL (0,021 L).
The chemical equation is:Ba(NO3)2 + Na2SO4 = BaSO4 + 2 NaNO3The volume (in mL) of 0,25M Na2SO4 solution needed to precipitate all the barium as BaSO4(s) from 12,5mL of 0,15M Ba(NO3)2 solution is 7,5 mL.
25.0 grams Na2SO4 ( only way this compound is possible ) 25.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams) = 0.176 moles Na2SO4 -----------------------------
Because Na2SO4 is an ionic compound and so does not have actual molecules.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
no
As sodium sulfite (Na2SO4) dissolves, it dissociates into its ions: Na2SO4 --> 2Na+ + SO32-
Na2SO4 + H2O = Na2SO4*10H2O > insoluble and foms clumbs what can be phisically separated from the solution
Seltzer is a solution of a gas(carbon dioxide) and water
103.6ºC
Na2SO4 +CaCl2---------------> 2NaCL +CaSo4
The molality is 0,07.
how man molecules are there in 450 grams of Na2SO4. the simple formula to determine of mole is NO OF MOL= GIVEN MASS IN gm/MOL:MASS OF COMP: , AND IMOL = 6.02X1023 . SO, 19. 077X1023 molecules are present in 450 grams of Na2SO4.
2C6H5COO-Na+ + H2SO4 ----> 2C6H5COOH + Na2SO4
22
The answer is 20,79 mL (0,021 L).