Sodium chloride is a solute when is dissolved in water (the solvent).
Need to find moles NaCl. 526 grams NaCl (1 mole NaCl/58.44 grams) = 9.0 moles NaCl --------------------------------now, Molarity = moles of solute/Liters of solution or, for our purposes Liters of solution = moles of solute/Molarity Liters of solution = 9.0 moles NaCl/3.0 M = 3.0 liters in volume ---------------------------------
The temperature of the solute (water for example) can be increased, as well as agitating the solute.
In a solution, the particles which are present in larger quantity are called solvent and the particles which are present in smaller quantity are called solute. For example, in aqueous NaCl solution: NaCl is the solute particle and H2O is the solvent.
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
The solute is of course sodium chloride (NaCl) and the solvent is generally water.
The solute (NaCl) is dissolved in the solvent (water)
This is a solution of sodium chloride (NaCl) in water.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
Sodium chloride is the solute and the concentration is 55,8 g/L.
m (molality)=moles of solute/kg of solvent To calculate moles of solute you convert 292.5 g of NaCl to moles of NaCl. So (292.5gNaCl)(1mole NaCl / 58.4gNaCl)= 5.0085 moles NaCl Now plug and chug. 0.25m=5.0085moles NaCl / x x=5.0085 moles NaCl /.25m x=20kg
No, not exactly.Mass mass percent concentration measures grams of solute per 100 grams of solution (= solvent + solute)Example:58.5 g NaCl (solute) added to941.5 g H2O (solvent) gives you1000.0 g solution of 5.85% NaCl (= 100%*58.5/1000.0),which is about a 1.0 mol/L NaCl solution.