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The potential difference across two resistors connected in parallel to a battery with a potential difference of 6 volts is 6 volts. Kirchoff's Voltage Law: The signed sum of the voltage drops in a series circuit is zero. This means that that the two series circuits involving the battery and each resistor have the same voltage across each other, and the series circuit involving the two resistors have the same voltage across each other.
If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.
This depends on the actual battery and what it is made of. A 1.2 volt rechargable NiMh battery typically gives off a voltage of 1.3 to start with, then it rapidly goes down to 1.2 volt where it stays stable until almost empty, then it quickly drops below and down to .5 volt or even further down.. The same applies to Lead Acid or NickelCadmium batteries. Different types of batteries have different properties. NickelCadmium normally are able to give a lot of current until empty. where as the current you get from a NiMh battery is rather limited. Lead Acid are capable of a very high current but still dependant on the internal design of the battery. Unfortunately one can not give a correct (for all) answer to a general question. Regards.
The increase in current (assuming resistance is the same and increase in voltage will lead to an increase in current) will fry your portable radio.
6 volts
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