How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
solution
6 litres of 40% and 2 litres of 80%.
You need 1 1/3 quarts of pure antifreeze.
0.6 of a pint.
6 litres of the 30% and 4 litres of 60%.
During the summer your engine would actually run hotter because antifreeze has a lower specific heat than does water. (That means a pure antifreeze solution will act as a better insulator than water---less heat will be transferred through the pure antifreeze solution.) Even during the winter, a 100 percent antifreeze solution isn't a good idea. A pure antifreeze solution actually provides less protection against freezing than does a mix solution.
Nothing, you have a solution of antifreeze. However if you then cool the solution the freezing point will be lower than that of pure water.
Solution.
4 gallons Let x be the amount of antifreeze needed to be added. We know that the total amount of antifreeze in the new solution must equal the amount of antifreeze in the old solution + x: .40*(x+12)=x+.20*12 .60x=2.40 x=4 gallons
You will need 3.2 gallons.
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.