The Cl- ions in HCl is oxidized to Cl2
b. Fe3 plus ions
When 90.0mL of 0.10M Fe3 plus 3 is added to 10.0 mL of SCN minus 1, you get an equilibrium molar concentration of FeNCS plus 2. This is determined from a calibration curve of 1.0x10-6 mol/L.
Aluminium.
The answer is 3. Fe -> Fe3+ + 3e
Fe^3+ ion forms the complex with SCN- , forming [FeSCN]2+
Cu is being reduced and Zn is being oxidized, hence Zn + CuSO4 --> ZnSO4 + Cu
FeCl3
sodium, Na is oxidized
The Cl- ions in HCl is oxidized to Cl2
b. Fe3 plus ions
Metals all prefer to loose electrons (sodium -> Na+, Fe - > Fe3+ etc.) S they prefer to be oxidised (oxidation is electron loss).
NAD+ is the oxidized and NADH is the reduced form.
When 90.0mL of 0.10M Fe3 plus 3 is added to 10.0 mL of SCN minus 1, you get an equilibrium molar concentration of FeNCS plus 2. This is determined from a calibration curve of 1.0x10-6 mol/L.
Mg++ is fully oxidized.
Hg will have 80 electrons.
FeBr2 + H3PO4 <--> Fe3(PO4)2 + HBr