25.5molecule
The density of potassium chloride is 1.98 g/cm3. If someone is short in potassium in his/her body, he/she needs to use this supplement. The drug class is Potassium Salt.
There are three properties that can be used and they are the boiling point elevation, freezing point depression, and osmotic pressure. The molar mass is equal to mass of the unknown divided by the moles of the unknown.
its equal number of electrons wich less from componed
The molar mass of Hydrogen Chloride (HCl) is 36.46 g/mol It is made up of equal parts of Hydrogen (molar mass 1.007) and Chlorine (molar mass 35.453)
The mass in grams of a substance that equals one mole of that substance is the molecular weight of the substance, which can be found by adding the atomic weights of all the atoms in the molecule. For C2O2H4, the molecular weight would be (12 x 2) + (16 x 2) + (1 x 4) = 60 g/mol.
Since potassium has a valence of one, its equivalent weight is the same as its molecular weight; therefore, 2.9.
The density of potassium chloride is 1.98 g/cm3. If someone is short in potassium in his/her body, he/she needs to use this supplement. The drug class is Potassium Salt.
Any fraction divided by an equivalent fraction will always equal one.Any fraction divided by an equivalent fraction will always equal one.Any fraction divided by an equivalent fraction will always equal one.Any fraction divided by an equivalent fraction will always equal one.
Molecular weight.
The equivalent weight is the gram molecular weight divided by the number of electrons lost or gained by each molecule; e.g., potassium permanganate (KMnO4) in acid solution, 158.038/5 g; potassium dichromate (K2Cr2O7), 294.192/6 g; and sodium thiosulfate (Na2S2O3·5H2O), 248.1828/1 g. In case of Sodium Thiosulfate the reation proceeds as under: I2 + 2 Na2S2O3 → Na2S4O6 + 2 NaI 2 Na2S2O3 ≡ I2 ≡ Cl2 ≡ 2 e Hence Na2S2O3 ≡ 1 e Thus Molecular weight devded by 1 is the equivalent weight & hence both have same value
These statements may be helpful for answering this question: Normality is equal to the number of equivalent weights of solute per Liter of solution. Molarity is equal to the number of moles of solute per Liter of solution, and to determine the number of moles, you take the weight of the solutes in solution divided by the weight of one of those solute molecule (the molecular weight). How does one relate equivalent weights to moles. The equivalent weight of a compound is equal to its molecular weight divided by its valence. The valence in this context means the same thing as the number of substitutable groups (H+s or OH-s). Carbonic acid is a diprotic acid that dissociates to release 2 ionizable H+ s. So along those lines, a 1 M solution of H2CO3 is equivalent to a 2N solution of H2CO3. If 1 molar H2CO3 = 2N H2CO3 , a 2.4 M H2CO3 with 2 ionizable groups x 2.4, or 4.8N. Sorry if you got my first answer and that confused you, the second answer (4.8) is the correct one. I confused normality with equivalent weight. The equivalent weight of an acid with a valence >1 like H2CO3 (valence = 2) is in fact less than its molecular weight, but the question was about normality, the number of equivalents present in a liter of solution which is not the same as the equivalent weight.
Yes, it is
Normality is a way of expressing concentration, and is not used widely any more. It is the equivalent wt of a substance per liter of solution. The equivalent weight will depend on the reaction that take place, and can be the same as the molecular weight. Example: HCl has same equiv. wt. as mol. wt. because it has only 1 equivalent, i.e. one H. H2SO4 has TWO equivalents (2 H+) so, 1 molecular wt will be equal to 2 equivalent wts, and normality will be 2x the molarity.
It's the molecular weight divided by 22.4 L/moles. 6.52 g/L is the answer. The molecular weight is 146.05. That number is what one sulfur and six flourides equal.
No - strictly speaking the number of moles is the weight/molecular weight
The a.m.u. is defined as the fraction of 1/12 of an atom of the carbon-12 isotope. The value is pretty nearer to the mass of a hydrogen atom. Therefore, in every compound, the gram molecular weight is numerically equal to the molecular mass in atomic mass units. Therefore the gram molecular weight of NaOH is 40 g/mol.
0.1385