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Is horizontal component of velocity is constant for ball thrown upward?
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A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
How are the horizontal velocity and the vertical velocity of thrown objects related?
If you can ignore air resistance, they're not. Neither component has any influence on the other one unless the object is acting as an airfoil.
What is the curved path an object follows when thrown?
If there's no influence from air resistance, then the path of a "projectile" is a parabola. That's what you get when one component of velocity is constant and its other (orthogonal) component is accelerated.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
A projectile is thrown with an initial velocity which has a horizontal component of 4 m s What will be its horizontal speed after 3s?
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
How are the horizontal velocity and the vertical velocity of thrown objects related?
If you can ignore air resistance, they're not. Neither component has any influence on the other one unless the object is acting as an airfoil.
What is the curved path an object follows when thrown?
If there's no influence from air resistance, then the path of a "projectile" is a parabola. That's what you get when one component of velocity is constant and its other (orthogonal) component is accelerated.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
A ball is thrown straight up At the top of its path its instantaneous speed is?
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
How can you used trigonometry in projectile motions?
when a body is thrown at an angle in a projectile motion, the vertical component of the velocity is vcos(B) ..where v is the velocity at which the body is thrown and B represents the angle at which it is thrown.Similarly horizontal component is vsin(B). these components are useful in determining the range of the projectile ,the maximum height reached,time of ascent,time of descent etc.,
A banana is thrown straight out so it has both horizontal and vertical velocity After 1 second, what is its vertical velocity?
9.8
How do you find time of flight from initial velocity and an angle at which an object is thrown?
If you're willing to ignore the effect of air resistance, then the answer is as follows: The object's horizontal velocity remains constant (at least until it eventually hits the ground). The vertical component of the object's initial velocity ... call it V(i) ... is the (total initial velocity) multipled by the (sine of the initial angle above the horizontal). Beginning at the time of the toss, the magnitude of the vertical component of velocity is V = V(i) - 1/2gT2. T = number of seconds after the toss g = acceleration of gravity = approx 32 ft/sec2 or 9.8 m/sec2
What is the velocity of a ball thrown 20 ft in 4 seconds?
In the case of constant velocity (or speed), velocity = distance / time.
When a stone is thrown upward at an angle what happens to the vertical component of its velocity as it rises and as it falls?
The vertical component of its velocity increases at the rate of 9.8 meters (32.2 feet) per second downward every second. Without involving numbers, simply the vertical component will first be upward at what ever velocity it is when split from the horizontal velocity, then (after reaching the peak of its height at which velocity is zero) it will be a downward vector that, yes, will increase with acceleration due to gravity (which is where the 9.8 meters per second squared came from)
Which is the total velocity of a projectile at maximum height?
It depends. If the projectile goes straight up and straight down, its velocity will be zero at the top. If the projectile is a baseball about halfway between the pitcher and the bat, its velocity might be 150 km/h.
