Metallic sodium, in an atmosphere of chlorine gas, would burn very vigorously, producing NaCl. Of course, salt is a very abundant compound in our world, so it would never actually be necessary to produce it by this method.
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
NaCl---------------→Na+ + Cl-
The equation is: NaCl----------Na++ Cl-
Na+ + Cl- --> NaCl NaCl = salt.
Sodium and chlorine can be separated from NaCl by electrolisys.
Na+ + Cl- --> NaCl NaCl = salt.
NaCl --> Na+ + Cl- You could write water on either side I suppose, but it is negligible. I've also seen H2O written over the arrow.
The percentage of chlorine in NaCl is 60,33417 %.
58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-
NaCl-----------------Na+ + Cl-is a dissociation reaction.
Na^(+) + Cl^(-) = NaCl(s)
1ppm = 1mg/lso, 1000ppm = 1gm/l or 0.1gm/100ml that is your required.FW of NaCl = 58.5 (Na-23+Cl-35.5)58.5gm NaCl = 23gm NaXgm NaCl = 0.1gm Natherefor X = 0.2543gmSo dissolve 0.2543gm of NaCl to 100ml, to get 1000ppm of 100ml Na soln.