Yes this should be correct. Fluorine needs one electron to complete the shell, which will give fluoride a -1 charge.
The oxidation number for the ion fluoride Fl- is always -1 in compounds. If you meant the element fluorine F2, then the oxidation number is 0.
The oxidation number of an atom states how it shares its valence electrons with other elements (or ions or compounds). A neutral atom always has its oxidation number 0: it does not share any electrons. A cation has a positive oxidation number and that of anion is negative because they donate and attract electrons respectively.
Group 1 elements have +1 oxidation number (except for hydrogen) All group 2 elements have +2 oxidation number Fluoride ion always has -1
Oxygen pretty much always has an oxidation number of -2 (there are few exceptions.) A better question is "What is arsenic's oxidation number in this ion?" It would be +5.
Helium does not form any known stable compounds, and thus it is nearly always in the 0 oxidation state.
The oxidation number for the ion fluoride Fl- is always -1 in compounds. If you meant the element fluorine F2, then the oxidation number is 0.
The oxidation number of an atom states how it shares its valence electrons with other elements (or ions or compounds). A neutral atom always has its oxidation number 0: it does not share any electrons. A cation has a positive oxidation number and that of anion is negative because they donate and attract electrons respectively.
The oxidation number of an atom states how it shares its valence electrons with other elements (or ions or compounds). A neutral atom always has its oxidation number 0: it does not share any electrons. A cation has a positive oxidation number and that of anion is negative because they donate and attract electrons respectively.
Group 1 elements have +1 oxidation number (except for hydrogen) All group 2 elements have +2 oxidation number Fluoride ion always has -1
Oxygen pretty much always has an oxidation number of -2 (there are few exceptions.) A better question is "What is arsenic's oxidation number in this ion?" It would be +5.
Helium does not form any known stable compounds, and thus it is nearly always in the 0 oxidation state.
0 in the elemental form, +2 in its compounds.
Zero. Elemnts always have a zero oxidation state hoever they are bonded. Helium is a noble gas, monoatomic and forms no compounds so as it happens it is always zero.
To calculate the oxidation state of fluorine in O2F2, first draw a diagram of the molecule: F-O-O-F Determine the most electronegative atom(s), which are fluorines -- the most electronegative atom there is. Being in the group 7A, a fluoride ion would gain an electron to a -1 charge, so each has an oxidation number of -1. The oxygens, therefore, have an oxidation number of +1 each.
The oxidation number is 0. The sum of all oxidation number in a molecule that has not charge is always 0. If it has a charge (ion negative or positive) then the sum must be equal to the charge number.
Yes, always in its ionic oxides and usually in other compounds.
For ionic compounds such as the one mentioned above, naming them is relatively easy. As we all know, an ionic compound consists of a metal ion(which is usually positive) and a negative ion. Hence, the names for metallic compounds are always in the following format: Name of metal + Name of negative ion However, do take note that for transition metals, the oxidation state has to be included. This is because transition metals have multiple oxidation states. The oxidation state of the metal is presented by: Metal (oxidation number). For example, rust is Iron (III) oxide. Cr2O3 is hence named chromium (III) oxide.