It doesn't matter as long as you measure both voltage and current in same units.
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
Current
Ohms law does not consider inductance
no
Vpp is Peak-to-Peak voltage, in other words, in AC voltage, the peak-to-peak voltage is the potential difference between the lowest trough in the AC signal to the highest. Assuming the reference to the voltage is zero, Vpp would be twice the peak voltage (between zero and either the highest or lowest point in the AC waveform). Vrms is the Root Mean Square voltage, think of it as sort of an average (it's not quite that simple). For a sine wave, the RMS voltage can be calculated by y=a*sin(2ft) where f is the frequency of the signal, t is time, and a is the amplitude or peak value.
Vrms = Vpp/squareroot(2)This can be written another way:Vrms * squareroot(2) = VppAnswerThe question asks for the relationship between the rms value of voltage, and the peak-to-peak value of voltage, not the peak value (Vmax) of voltage, so:Vp-p = 2 Vmax = 2(1.414) Vrms = 2.828 Vrms
For a sine wave, the form factor is the square root of 2. Thus, the effective voltage of 56 V (56 Vrms) is 2-1/2 times the peak-to-peak voltage. Thus, the peak-to-peak voltage Vpp = Vrms * sqrt(2)In this example:Vpp = 56V * 1.4142... = 79.2V (rounded to one decimal place)
ohms law.
Vrms=sqaure root(3kT/m)
To find the conductance using ohms law,you take the inverse of the resistance(/R)
1982The VPP was created in 1982.
Current
No.
no
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Ohms law does not consider inductance
no