To conver Vrms in to Voltage Source we useVm=√2 (vi)
VRMS = 1/N times square root of [ sum(Vn2) ]
Vrms=Vm/1.414................... from this u can find Vm.....magnitude of voltage.
The formula of the root mean square speed is: vrms = √(3RT/Mm) where: R = molar gas constant T = temperature in Kelvin Mm = molar mass
Approx. 280 VRMS. Vpeak * 0.707 = Vrms
Many can measure both - Vrms (AC) or DC voltage.
Vrms = Vpp/squareroot(2)This can be written another way:Vrms * squareroot(2) = VppAnswerThe question asks for the relationship between the rms value of voltage, and the peak-to-peak value of voltage, not the peak value (Vmax) of voltage, so:Vp-p = 2 Vmax = 2(1.414) Vrms = 2.828 Vrms
Actually ,Vrms is the root mean square voltage for example, consider voltages 5V,10V,2V So Vrms is the root value of {[(5*5)+(10*10)+(2*2)]/3} And Vpeak is 10V Thanks!!!!!(Zayed)
238
Vp=2 Vdc=50 r=Vrms/Vdc Vrms=Vp/1.121 so r=0.028
KVA is an acronym for killo volt - amperes. It is a measure of power (both real and reactive) defined as P = Vrms * Irms. If there is a power factor associated with this, it can be used to separate the real and reactive power:P(real) = Vrms * Irms * pfP(reactive) = Vrms * Irms * (1 - pf)
RMS*SQRT(2)=V(peak)or115V*1.414= 162.63V(peak)Source: What_is_the_conversion_for_rms_voltage_to_peak_to_peak_voltage